Ani*_*ket 7 google-cloud-storage google-cloud-platform terraform terraform-template-file terraform-provider-gcp
我创建了一个 terraform 文件来创建具有公共可读存储对象权限的 Google 存储桶。我能够部署存储桶,但无法针对我的模板分配正确的 ACL,我发现 ACL 部分有一些错误。
provider "google-beta" {
project = "${var.project}"
}
resource "google_storage_default_object_access_control" "public_rule" {
bucket = "google_storage_bucket.test-${var.project}"
role = "READER"
entity = "allUsers"
}
resource "google_storage_bucket" "bucket" {
name = "test-${var.project}"
storage_class = "standard"
location = "US"
}
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如果有人可以帮助我在创建存储桶时分配权限,那就太好了。
根据Terraform 官方文档,使用该函数bucket.name,并从变量中读取存储桶名称name。您必须在resource_storage_bucket下面提供您的项目 ID。我尝试过,它对我来说工作正常:
provider "google-beta" {
}
resource "google_storage_default_object_access_control" "public_rule" {
bucket = google_storage_bucket.bucket.name
role = "READER"
entity = "allUsers"
}
resource "google_storage_bucket" "bucket" {
name = "[THE_BUCKET_NAME]"
project = "[PROJECT_ID]"
storage_class = "standard"
location = "US"
}
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哪里PROJECT_ID是您的项目 ID,THE_BUCKET_NAME哪里是您要放置的存储桶名称。
以下设置解决了我的问题:
provider "google-beta" {
project = "${var.project}"
}
data "google_iam_policy" "viewer" {
binding {
role = "roles/storage.objectViewer"
members = [
"allUsers",
]
}
}
resource "google_storage_bucket_iam_policy" "editor" {
bucket = "${google_storage_bucket.bucket.name}"
policy_data = "${data.google_iam_policy.viewer.policy_data}"
}
resource "google_storage_bucket" "bucket" {
name = "${var.project}-xxxx"
storage_class = "xxxxx"
location = "xxxxxxx"
}
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