如何解决laravel中的歧义列问题？

Question

我创建了一个全局范围，以便仅获取列状态 = 1 的数据。它运行良好。但是我在我的代码中遇到了这个问题，我不知道如何解决这个问题：

"message": "SQLSTATE[23000]: 完整性约束违规：1052 where 子句中的列 'status' 不明确（SQL: select items.*, item_orders. order_idas pivot_order_id, item_orders. item_id as pivot_item_id, item_orders. quantityas pivot_quantityfrom itemsinternal join item_orderson items. id= item_orders. item_idwhere item_orders. order_id= 1和 status= 1 个按id降序排列的订单)",

这是我的代码：

$order =  Order::find($id);

       if (is_null($order) || empty($order))
           return ResponseHelper::customizedResponse(false,'4500','No Order is available');

       $user =$order->user_id;

       $place = Place::where('id',$order->place_id)->first();

       $orderItems = ItemOrder::where('order_id',$order->id)->get()->toArray();

       $orderArray = [];
        $itemQ = [];
       foreach ($orderItems as $orderItem)
       {
           $orderArray[] =$orderItem['item_id'];
           $itemQ[] = $orderItem['quantity'];
       }

        $items = Item::whereIn('id',$orderArray)->get();

        $itemP = [];
        foreach ($items as $item)
        {
            $itemP[]= $item->price;
        }

        $totalItem = array_map(function ($price,$quantity){
            return $price * $quantity;
        },$itemP , $itemQ );


        $total = array_sum($totalItem);
        $customer = User::find($user);

        $address = Address::where('user_id',$customer->id)->first();

       return response()->json(['order'=>$order,'place'=>$place,'items'=>$items,'customer'=>$customer,'address'=>$address,'total'=>$total]);

全球范围：

public function apply(Builder $builder, Model $model)
    {
        if (str_contains(request()->route()->uri(),'api')) {

            $builder->where('status', '=', 1);
        }
    }

Answer 1

这意味着您有status多个表，您需要通过表名指定表的列，

像这样：

$builder->where('item_orders.status', '=', 1);

// In your case: you can use your $model to get the table's name
$builder->where($model->getTable().".status", 1);