使用foreach()循环遍历对象并更改值

Question

我有一个问题循环通过一个对象(stdObject)并改变一个值.

会发生什么:

• 查询结果出现在函数中.
• 它将对象提取到'数组'
• 之后,我需要使用html_entity_decode()将对象内的内容解码&为可读字符...

这就是出了什么问题.我不知道如何将转换后的字符串放回到对象中.

这是这个函数的代码.

function jsonRequestHandlerUTF8($query) {
    $id = "0";
    $message = errorHandler($id);
    $a_result = array();
    if (mysql_num_rows($query) == 0) {
        //Empty sql query
        $id = '1';
        $a_result = jSONErrorObject($id);
    } else {
        //No error occurred
        $a_result['ExceptionId'] = $id;
        $a_result['ExceptionMessage'] = $message;
        $a_result['Items'] = null;
        while ($my_result = mysql_fetch_object($query)) {
            $a_result['Items'][] = $my_result;
        }

        $test = $a_result['Items'];
        foreach ($test as $v1) {
            foreach ($v1 as $v2) {
                $v2 = html_entity_decode($v2, ENT_QUOTES, "utf-8") . "\n";
// Here should be code to get the $v2 inside the object again.....                
            }
        }
}
    $a_result = json_encode($a_result);
    return $a_result;
}

$ a_result ['Items']看起来像这样:

Array
(
    [0] => stdClass Object
        (
            [idziekmeldingen] => 1
            [meldingID] => 13190
            [title] => Ziekmelding: Alex
            [published] => 2011-05-09
            [updated] => 2011-05-09
            [content] => Per 9-05-2011 heeft Alex zich ziek gemeld.
            [location] => AP
            [institute] => CMI
            [lastCron] => 2011-05-11 11:32:54
        )

    [1] => stdClass Object
        (
            [idziekmeldingen] => 2
            [meldingID] => 12933
            [title] => Ziekmelding: Rimmert
            [published] => 2011-04-26
            [updated] => 2011-04-26
            [content] => Per 26-04-2011 heeft Rimmer zich ziek gemeld.Met vriendelijke groet,Luciënne Plomp
            [location] => AP
            [institute] => CMI
            [lastCron] => 2011-05-11 11:32:54
        )
)

Answer 1

使用&符号将变量传递给循环引用.这意味着您要修改实际变量而不是它的副本.

foreach ($test as &$v1) {
    foreach ($v1 as &$v2) {
        $v2 = html_entity_decode($v2, ENT_QUOTES, "utf-8") . "\n";               
    }
}

(注意,这仅适用于PHP 5.0及更高版本....但如果您仍在使用PHP4,则确实需要升级!)

Answer 2

来自文档:

从PHP 5开始,您可以通过在$前加上$来轻松修改数组的元素.这将分配引用而不是复制值.

使用引用并分配到当前值.