Python:Web Scraping - Airbnb 获取列表的纬度和经度值

fon*_*men 2 python coordinates web-scraping airbnb-js-styleguide

我正在尝试获取出现在 Airbnb 中的房源的纬度和经度,我认为该信息位于嵌入式谷歌地图中。当我尝试通过使用 lxml 库或 Beautiful Soup 复制完整的 Xpath 来抓取该对象时,我无法获得它。例如列表https://www.airbnb.co.uk/rooms/15307317,在地图中心具有经度和纬度信息的对象,带有标签 div img 和属性 data-veloute = "map/GoogleMapStatic ",我尝试使用以https://maps.googleapis.com/maps/api/staticmap?center=开头的链接,但我无法用我的代码识别正确的对象。

url = 'https://www.airbnb.co.uk/rooms/15307317'
response = http.request('GET', url)
soup = BeautifulSoup(response.data, 'lxml')
soup.find("div", {"data-veloute":"map/GoogleMapStatic"})
soup.find("img", {"data-veloute":"map/GoogleMapStatic"})
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或使用下一个代码:

resp = requests.get(url, headers=headers)
tree = html.fromstring(resp.content)
tree.xpath('/html/body/div[5]/div/main/div/section/div/div[2]/div/div[2]/div[1]/div/div[10]/div/div/div/div/div/section/div[2]/div[2]/div[2]/img')
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有没有可能得到这些信息?

小智 5

正如 RafalS 建议的那样,您应该使用selenium或其他浏览器脚本库。

这是我想出的。

from selenium import webdriver
from selenium.webdriver.chrome.options import Options 
import time
from bs4 import BeautifulSoup
import urllib.parse as urlparse
from urllib.parse import parse_qs

def main():
    chrome_options = Options()  
    chrome_options.add_argument("--headless")  #if you don't want the GUI to pop up
    driver = webdriver.Chrome(options=chrome_options)
    driver.get('https://www.airbnb.co.uk/rooms/15307317')
    time.sleep(2)
    soup = BeautifulSoup(driver.page_source, "lxml")
    url = (soup.find("img", {"data-veloute":"map/GoogleMapStatic"})).attrs['src']
    parsed = urlparse.urlparse(url)
    print(parse_qs(parsed.query)['center'])

if __name__ == '__main__':
    main()
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输出:

['53.8147,-1.52538']
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