在c#中从XLSX读取数据

Question

我是c#的新手,我正在尝试使用以下代码在c#中读取XLSX文件:

string Connection = "Provider=Microsoft.ACE.OLEDB.12.0;DataSource=c:\\Temp\\source.xlsx;Extended Properties=\"Excel 12.0;HDR=Yes;IMEX=1\";";

//code to read the content of format file 
OleDbConnection con = new OleDbConnection(Connection);
OleDbCommand command = new OleDbCommand();

DataTable dt = new DataTable();
OleDbDataAdapter myCommand = new OleDbDataAdapter("select * from [Tabelle1$]", con);

myCommand.Fill(dt);
Console.Write(dt.Rows.Count);

我从输出中得到了正确的数,但我还有两个问题:

1.如何选择where语句(如何访问行)？

 select * from [Tabelle1$] where A = '123' (A being an existing Excel row)

将提出错误参数的错误...

2.can可以为我提供教程链接或简短示例如何访问数据吗？

Answer 1

请参考以下示例代码:

private DataTable LoadXLS(string strFile, String sheetName, String column, String value)
{
    DataTable dtXLS = new DataTable(sheetName);

    try
    {
       string strConnectionString = "";

       if(strFile.Trim().EndsWith(".xlsx")) {

           strConnectionString = string.Format("Provider=Microsoft.ACE.OLEDB.12.0;Data Source={0};Extended Properties=\"Excel 12.0 Xml;HDR=YES;IMEX=1\";", strFile);

       } else if(strFile.Trim().EndsWith(".xls")) {

           strConnectionString = string.Format("Provider=Microsoft.Jet.OLEDB.4.0;Data Source={0};Extended Properties=\"Excel 8.0;HDR=Yes;IMEX=1\";", strFile);

       }

       OleDbConnection SQLConn = new OleDbConnection(strConnectionString);

       SQLConn.Open();

       OleDbDataAdapter SQLAdapter = new OleDbDataAdapter();

       string sql = "SELECT * FROM [" + sheetName + "$] WHERE " + column + " = " + value;

       OleDbCommand selectCMD = new OleDbCommand(sql, SQLConn);

       SQLAdapter.SelectCommand = selectCMD;

       SQLAdapter.Fill(dtXLS);

       SQLConn.Close();
    }

    catch (Exception e)
    {
       Console.WriteLine(e.ToString());
    }

    return dtXLS;

}