How do I include all records 5 Days after date index

Question

I have a data table, let's call it dt and a date index table, let's call it dt_idx. I would like to get:

1. all records from dt where dt.date = dt_idx.date AND
2. all records from dt where dt.date is 1-5 days later from every dt_idx.date. (NOTE: DO NOT ASSUME dt.date IS CONSECUTIVE, dates could be missing)

Here is a sql fiddle: Click Here

Here is a sample schema:

CREATE TABLE dt_idx
(
  d DATE,
  v INT
)
GO

INSERT INTO dt_idx (d, v)
SELECT '2019-02-10', CAST(RAND(CHECKSUM(NEWID())) * 1000 as INT) + 1
UNION
SELECT '2019-03-05', CAST(RAND(CHECKSUM(NEWID())) * 1000 as INT) + 1


CREATE TABLE dt
(
  d DATE,
  a int,
  b int
)

declare @sdate date = '2019-01-01'
    , @edate date = '2019-03-24'

; with dates_CTE (date) as (
        select @sdate 
    Union ALL
        select DATEADD(day, 1, date)
        from dates_CTE
        where date < @edate
) select *
into #temp
from dates_CTE 

INSERT INTO dt(d, a, b)
SELECT date, CAST(RAND(CHECKSUM(NEWID())) * 1000 as INT) + 1, CAST(RAND(CHECKSUM(NEWID())) * 1000 as INT) + 1
from #temp

Here is the output I am expecting (columns a & b would be some random numbers as per the table):

d           |    a  |   b
2019-02-10     123     123
2019-02-11     234     344
2019-02-12     234     344
2019-02-13     234     344
2019-02-14     234     344
2019-03-05     234     344
2019-03-06     234     344
2019-03-07     234     344
2019-03-08     234     344
2019-03-09     234     344

Answer 1

您的问题有点难以理解。我认为您希望其中的所有记录dt都比中的记录晚零到五天dt_idx。

如果是这样，您可以使用exists：

SELECT *
FROM dt
WHERE EXISTS (SELECT 1
              FROM dt_idx di
              WHERE dt.d >= di.d AND
                    dt.d < DATEADD(day, 5, di.d)
             );