Dan*_*ara 3 python return function return-value python-3.x
例如,现在每次我使用 cost = get_cost() 时,该函数都会通过并再次要求输入。有没有办法只保存返回值,以便我可以在另一个函数中使用该值?感谢所有的帮助。
def get_cost():
cost = float(input('Please Enter the Cost of the Meal: '))
while cost <= 0:
print('The Cost Must Be Greater Than 0!')
cost = float(input('Please Enter the Cost of the Meal: '))
else:
return cost
def compute_tip():
cost = get_cost()
finalTip = cost * 0.18
return finalTip
def compute_tax():
cost = get_cost()
finalTax = cost * 0.0825
return finalTax
def compute_grand_total():
cost = get_cost()
finalTip = compute_tip()
finalTax = compute_tax()
grandTotal = cost + finalTip + finalTax
return grandTotal
def display_total_cost():
cost = get_cost()
finalTip = compute_tip()
finalTax = compute_tax()
grandTotal = compute_grand_total()
print('Cost\t$', format(cost, '.2f'))
print('Tip\t$', format(finalTip, '.2f'))
print('Tax\t$', format(finalTax, '.2f'))
print('Total\t$', format(grandTotal, '.2f'))
def main():
get_cost()
compute_tip()
compute_tax()
compute_grand_total()
display_total_cost()
main()
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小智 5
看起来你的主函数只需要包含一个函数调用
def main():
display_total_cost()
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因为display_total_cost()根据需要在内部调用所有其他函数。
然后您可以将cost函数参数作为函数参数传递给需要它的其他函数,并删除get_cost所有其他函数的调用。这是您的脚本的更新版本:
def get_cost():
cost = float(input('Please Enter the Cost of the Meal: '))
while cost <= 0:
print('The Cost Must Be Greater Than 0!')
cost = float(input('Please Enter the Cost of the Meal: '))
else:
return cost
def compute_tip(cost):
finalTip = cost * 0.18
return finalTip
def compute_tax(cost):
finalTax = cost * 0.0825
return finalTax
def display_total_cost():
cost = get_cost()
finalTip = compute_tip(cost)
finalTax = compute_tax(cost)
grandTotal = cost + finalTip + finalTax
print('Cost\t$', format(cost, '.2f'))
print('Tip\t$', format(finalTip, '.2f'))
print('Tax\t$', format(finalTax, '.2f'))
print('Total\t$', format(grandTotal, '.2f'))
def main():
display_total_cost()
# common practice is to include this line
if __name__ == "__main__":
main()
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