SQL Server 2008:如何选择字段具有全部大写字母的所有行？

Question

这就是我的想法,我知道在这个领域,第一个单词总是至少2个字符.

Select *  
From Table!
where SUBSTRING(Name, 1, 3) like '[A-Z]'

但是,这会带回非大写字母的任何想法吗？

Answer 1

Select ...
From MyTable
Where Name Not Like '%[^A-Z]%' Collate SQL_Latin1_General_CP1_CS_AS

应该注意的是,这也将排除AZ之外的数字和字符.如果你想要包含非拉丁大写字符,你真的需要使用该Upper函数和Collate谓词:

Select ...
From MyTable
Where Name = Upper(Name) Collate SQL_Latin1_General_CP1_CS_AS

测试脚本:

With TestData As
    (
    Select '012324' As Name
    Union All Select 'ABC'
    Union All Select 'abc'
    Union All Select 'aBc'
    Union All Select 'ABé'
    Union All Select 'ABÉ'
    )
Select *
From TestData
Where Name = UPPER(Name) Collate SQL_Latin1_General_CP1_CS_AS

结果:

012324
ABC
ABÉ