use*_*147 5 oracle plsql sequences
希望有人能提供帮助.当我尝试在表中插入某些内容时,它会给出错误,指出主键已经存在.所以我需要重置我的序列,以便它始终是max(id)+1.
该表称为"People",有2列(ID,Name).该序列称为SEQ.
我正在考虑做一个循环.从dual中选择SEQ.nextval n次.这个n = max(id)-SEQ.currval
这会是什么工作?以及如何将其添加到语法中?
非常感谢.
Fra*_*itt 16
declare
l_MaxVal pls_integer;
l_Currval pls_integer default - 1;
begin
select max(id)
into l_MaxVal
from people;
while l_Currval < l_Maxval
loop
select my_seq.nextval
into l_Currval
from dual;
end loop;
end;
Run Code Online (Sandbox Code Playgroud)
如果这是一次性的,你可以使用alter sequence alter sequence sequenceName increment by val; 而val是最大+1,然后调用get nextVal,然后将增量设置回1.
我把下面的内容放在一起,告诉你如何在没有循环的情况下完成它.
create sequence changeValue start with 18 increment by 1 nocache ;
select changeValue.nextval from dual ;
/
NEXTVAL
----------------------
18
set serveroutput on
declare
maxVal number := 24 ;
curVal number ;
diffVal number ;
incrementVal number ;
procedure alterSequence(seqName in varchar2, incVal in number) as
s varchar2(500);
begin
s := 'alter sequence ' || seqName || ' increment by ' || incVal ;
dbms_output.put_line(s);
execute immediate s;
end alterSequence;
begin
--(done in 11gr2 so if in earlier version select into)
curVal := changeValue.currval ;
dbms_output.put_line('curValue=>' || curVal );
diffVal := maxVal - curVal ;
dbms_output.put_line('diffVal=>' || diffVal );
alterSequence ( 'changeValue' , diffVal + 1 );
incrementVal := changeValue.nextval ;
dbms_output.put_line('incrementVal=>' || incrementVal );
alterSequence ( 'changeValue' , 1 );
curVal := changeValue.currval ;
dbms_output.put_line('curValue=>' || curVal );
end ;
/
curValue=>18
diffVal=>6
alter sequence changeValue increment by 7
incrementVal=>25
alter sequence changeValue increment by 1
curValue=>25
Run Code Online (Sandbox Code Playgroud)
或者更好,正如@Dave建议的那样,只需删除并重新创建具有可接受的Start With值的序列.
| 归档时间: |
|
| 查看次数: |
17400 次 |
| 最近记录: |