use*_*755 1 python pattern-matching python-3.x pyspark fpgrowth
我有一个包含“EVENT_ID”列的数据框,其数据类型为字符串。我正在运行 FPGrowth 算法,但抛出以下错误
Py4JJavaError: An error occurred while calling o1711.fit.
:java.lang.IllegalArgumentException: requirement failed:
The input column must be array, but got string.
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列 EVENT_ID 有值
E_34503_Probe
E_35203_In
E_31901_Cbc
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我正在使用下面的代码将字符串列转换为数组类型
df2 = df.withColumn("EVENT_ID", df["EVENT_ID"].cast(types.ArrayType(types.StringType())))
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但我收到以下错误
Py4JJavaError: An error occurred while calling o1874.withColumn.
: org.apache.spark.sql.AnalysisException: cannot resolve '`EVENT_ID`' due to data type mismatch: cannot cast string to array<string>;;
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如何将此列转换为数组类型或使用字符串类型运行 FPGrowth 算法?
请尝试以下操作。
In [0]: from pyspark.sql.types import StringType
from pyspark.sql.functions import col, regexp_replace, split
In [1]: df = spark.createDataFrame(["E_34503_Probe", "E_35203_In", "E_31901_Cbc"], StringType()).toDF("EVENT_ID")
df.show()
Out [1]: +-------------+
| EVENT_ID|
+-------------+
|E_34503_Probe|
| E_35203_In|
| E_31901_Cbc|
+-------------+
In [2]: df_new = df.withColumn("EVENT_ID", split(regexp_replace(col("EVENT_ID"), r"(^\[)|(\]$)|(')", ""), ", "))
df_new.printSchema()
Out [2]: root
|-- EVENT_ID: array (nullable = true)
| |-- element: string (containsNull = true)
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我希望它会有所帮助。
正如@pault 在他的评论中很好地指出的那样,更简单的解决方案如下:
In [0]: from pyspark.sql.types import StringType
from pyspark.sql.functions import array
In [1]: df = spark.createDataFrame(["E_34503_Probe", "E_35203_In", "E_31901_Cbc"], StringType()).toDF("EVENT_ID")
df.show()
Out [1]: +-------------+
| EVENT_ID|
+-------------+
|E_34503_Probe|
| E_35203_In|
| E_31901_Cbc|
+-------------+
In [2]: df_new = df.withColumn("EVENT_ID", array(df["EVENT_ID"]))
df_new.printSchema()
Out [2]: root
|-- EVENT_ID: array (nullable = false)
| |-- element: string (containsNull = true)
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