R:如何根据列名和行名合并两个矩阵？

Question

输入矩阵A.

       column1   column2   column3   column4
row1   0         1         0         0
row2   0         0         -1        0
row3   1         0         0         -1

输入矩阵B.

       column5   column6   column7   column8
row1   0         1         0         0
row2   0         0         -1        0
row4   1         0         0         -1

输出矩阵C.

       column1   column2   column3   column4    column5   column6   column7   column8
row1   0         1         0         0          0         1         0         0
row2   0         0         -1        0          0         0         -1        0
row3   1         0         0         -1         0         0         0         0
row4   0         0         0         0          1         0         0         -1

备注:矩阵A和矩阵B重叠了行的名称.但是,所有列的名称都不同.

Answer 1

您可以merge通过指定可选参数来执行此操作,by并all:

#Reading data
txt1 <- "column1   column2   column3   column4
row1   0         1         0         0
row2   0         0         -1        0
row3   1         0         0         -1
"

txt2 <- "column5   column6   column7   column8
row1   0         1         0         0
row2   0         0         -1        0
row4   1         0         0         -1
"
dat1 <- read.table(textConnection(txt1), header = TRUE)
dat2 <- read.table(textConnection(txt2), header = TRUE)

#Merge them together
merge(dat1, dat2, by = "row.names", all = TRUE)

会屈服

Row.names column1 column2 column3 column4 column5 column6 column7 column8
1      row1       0       1       0       0       0       1       0       0
2      row2       0       0      -1       0       0       0      -1       0
3      row3       1       0       0      -1      NA      NA      NA      NA
4      row4      NA      NA      NA      NA       1       0       0      -1

如果你想用零替换NA,这应该工作:

#Assign to an object
zz <- merge(dat1, dat2, by = "row.names", all = TRUE)
#Replace NA's with zeros
zz[is.na(zz)] <- 0