“不赞成使用type的同义词；在numpy的未来版本中，它将被理解为（type，（1，））/'（1，）type'。” TensorFlow中的问题

Question

我安装了TensorFlow 1.10.1，但是当我尝试导入TensorFlow时，它说我需要TensorFlow版本1.10.0。因此，我安装了它，现在收到以下警告：

>>> import tensorflow
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:516: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:517: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:518: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:519: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:520: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:525: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:541: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:542: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:543: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:544: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:545: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:550: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])

Answer 1

如果您使用的是TF 2.0，一种快速的解决方案是将numpy降级为1.16.4。（我使用1.17并收到了相同的警告消息）。

1. pip uninstall numpy 
2. pip install numpy==1.16.4

见这里（感谢ymodak）

Answer 2

这只是一个警告，而不是错误。因为您当前的numpy libray版本与tensorflow版本不兼容而发生。您需要降级numpy版本。

tensorflow 1.10.0有要求numpy<=1.14.5,>=1.13.3，但您必须安装一些更高的版本（此警告消息出现在最新的numpy版本1.17.0中）。

Answer 3

pip install "numpy<1.17"

恢复到 Numpy 1.16.4版

Answer 4

或者，人们可以让警告静音：

import warnings
warnings.simplefilter(action='ignore', category=FutureWarning)
import tensorflow as tf

这里建议使用这种方法：如何抑制熊猫未来警告？

Answer 5

我的 linux 笔记本电脑在 python3 v3.6 中使用 tensorflow 时遇到了同样的问题

实际上，您只需要更改 2 个文件中的一些行：

• 1

  ~/.local/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py

在你的情况下：

C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py

现在更改此代码：（第 516 行）

_np_qint8 = np.dtype([("qint8", np.int8, 1)])
_np_quint8 = np.dtype([("quint8", np.uint8, 1)])
_np_qint16 = np.dtype([("qint16", np.int16, 1)])
_np_quint16 = np.dtype([("quint16", np.uint16, 1)])
_np_qint32 = np.dtype([("qint32", np.int32, 1)])


# _np_bfloat16 is defined by a module import.

# Custom struct dtype for directly-fed ResourceHandles of supported type(s).
np_resource = np.dtype([("resource", np.ubyte, 1)])

通过此代码：

_np_qint8 = np.dtype([("qint8", np.int8, (1,))])
_np_quint8 = np.dtype([("quint8", np.uint8, (1,))])
_np_qint16 = np.dtype([("qint16", np.int16, (1,))])
_np_quint16 = np.dtype([("quint16", np.uint16, (1,))])
_np_qint32 = np.dtype([("qint32", np.int32, (1,))])

# _np_bfloat16 is defined by a module import.

# Custom struct dtype for directly-fed ResourceHandles of supported type(s).
np_resource = np.dtype([("resource", np.ubyte, (1,))])

你必须在这个文件上做同样的事情：

• 2

  ~/.local/lib/python3.6/site-packages/tensorboard/compat/tensorflow_stub/dtypes.py

在你的情况下：

C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard/compat/tensorflow_stub/dtypes.py

它会起作用。

Answer 6

最新的 numpy 发行说明（1.17）有：

Future Changes

Shape-1 fields in dtypes won’t be collapsed to scalars in a future version
Currently, a field specified as [(name, dtype, 1)] or "1type" is interpreted 
as a scalar field (i.e., the same as [(name, dtype)] or [(name, dtype, ()]). 
This now raises a FutureWarning; in a future version, it will be interpreted 
as a shape-(1,) field, i.e. the same as [(name, dtype, (1,))] or "(1,)type" 
(consistently with [(name, dtype, n)] / "ntype" with n>1, which is already 
equivalent to [(name, dtype, (n,)] / "(n,)type").

https://docs.scipy.org/doc/numpy/release.html

因此用你的表达：

In [123]: np.dtype([("qint8", np.int8, 1)])                                                                  
/usr/local/bin/ipython3:1: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  #!/usr/bin/python3
Out[123]: dtype([('qint8', 'i1')])

In [124]: np.dtype([("qint8", np.int8, (1,))])                                                               
Out[124]: dtype([('qint8', 'i1', (1,))])

In [125]: np.dtype([("qint8", np.int8)])                                                                     
Out[125]: dtype([('qint8', 'i1')])

In [126]: np.dtype([("qint8", np.int8, 2)])                                                                  
Out[126]: dtype([('qint8', 'i1', (2,))])

In [127]: np.__version__                                                                                     
Out[127]: '1.17.0'