Kis*_*rra 9 javascript typescript angular-cli angular
我正在按照angular 官方网站的说明将 angular 6 更新为 angular 7 。
在更新会话期间:
我输入了更新 v7 的 angular/cli 和核心的命令
$ ng update @angular/cli@v7 @angular/core@v7。
更新后我得到了Invalid rule result: Function().
这是命令提示符输出:
added 106 packages from 85 contributors, removed 5 packages, updated 5 packages, moved 1 package and audited 36489 packages in 39.604s
found 18 vulnerabilities (12 low, 1 moderate, 5 high)
run `npm audit fix` to fix them, or `npm audit` for details
Invalid rule result: Function().
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有谁知道我为什么收到消息?
这是package.json文件中的依赖项。
"dependencies": {
"@angular/animations": "^8.0.0",
"@angular/cdk": "^7.3.7",
"@angular/common": "^8.0.0",
"@angular/compiler": "^8.0.0",
"@angular/core": "^8.0.0",
"@angular/forms": "^8.0.0",
"@angular/http": "^6.0.3",
"@angular/material": "^7.3.7",
"@angular/platform-browser": "^8.0.0",
"@angular/platform-browser-dynamic": "^8.0.0",
"@angular/router": "^8.0.0",
"core-js": "^2.5.4",
"hammerjs": "^2.0.8",
"ngx-loading": "^3.0.1",
"rxjs": "6.5.2",
"underscore": "^1.9.1",
"zone.js": "^0.9.1"
},
"devDependencies": {
"@angular-devkit/build-angular": "~0.6.8",
"@angular/cli": "~7.3.9",
"@angular/compiler-cli": "^8.0.0",
"@angular/language-service": "^8.0.0",
"@types/jasmine": "~2.8.6",
"@types/jasminewd2": "~2.0.3",
"@types/node": "~8.9.4",
"bootstrap-sass": "^3.3.7",
"codelyzer": "~4.2.1",
"jasmine-core": "~2.99.1",
"jasmine-spec-reporter": "~4.2.1",
"karma": "~1.7.1",
"karma-chrome-launcher": "~2.2.0",
"karma-coverage-istanbul-reporter": "~2.0.0",
"karma-jasmine": "~1.1.1",
"karma-jasmine-html-reporter": "^0.2.2",
"karma-scss-preprocessor": "^3.0.0",
"protractor": "~5.3.0",
"ts-node": "~5.0.1",
"tslint": "~5.9.1",
"typescript": "~3.4.5"
}
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我花了很多时间来解决这个问题。与几乎所有这些 Angular 升级错误一样,非常值得将解决方案的 Angular 依赖项升级到同一主要版本中的最大版本(在我们的案例中为 6)。这应该是安全的,并且会引入 Angular 团队的任何补丁。
我将我的开发依赖项中的 Angular CLI 从 升级"@angular/cli": "6.0.3",到"@angular/cli": "6.2.9",. 在撰写本文时,这是同一主要版本中最新支持的版本。您可以使用以下命令来执行此操作:
ng update @angular/cli@6.2.9
此后,我能够运行ng update @angular/cli@7 @angular/core@7而不会遇到错误“无效的规则结果:Function()”。
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