Syd*_*ney 5 jquery jquery-plugins
我在http://docs.jquery.com/Plugins/Authoring上定义了我的插件
(function( $ ){
var methods = {
init : function( options ) { },
show : function( options ) { },
hide : function( ) { },
update : function( content ) {
// How to call the show method inside the update method
// I tried these but it does not work
// Error: not a function
this.show();
var arguments = { param: param };
var method = 'show';
// Error: options is undefined
methods[ method ].apply( this, Array.prototype.slice.call( arguments, 1 ));
}
};
$.fn.tooltip = function( method ) {
// Method calling logic
if ( methods[method] ) {
return methods[ method ].apply( this, Array.prototype.slice.call( arguments, 1 ));
} else if ( typeof method === 'object' || ! method ) {
return methods.init.apply( this, arguments );
} else {
$.error( 'Method ' + method + ' does not exist on jQuery.tooltip' );
}
};
})( jQuery );
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如何在update方法中调用show方法?
编辑:
该show方法引用this.使用methods.show(options)或methods['show'](Array.prototype.slice.call( arguments, 1 ));工作调用show方法,但然后引用this似乎是错误的,因为我收到了一个this.find(...) is not a function错误.
该show方法:
show: function(options) {
alert("Options: " + options);
alert("Options Type: " + options.interactionType);
var typeCapitalized = capitalize(options.interactionType);
var errorList = this.find('#report' + typeCapitalized);
errorList.html('');
},
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Mat*_*all 14
var methods = {
init : function( options ) { },
show : function( options ) { },
hide : function( ) { },
update : function( options ) {
methods.show.call(this, options);
}
};
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