Ste*_*gan 146

交叉连接只是两组笛卡尔积.它没有明确的连接运算符.

var combo = from p in people
            from c in cars
            select new
            {
                p.Name,
                c.Make,
                c.Model,
                c.Colour
            };

  • `people.SelectMany(p => cars,(p,c)=> new {...})` (41认同)
  • 您如何用lambda表示法写出`p来自汽车中c来自人中c来自汽车中c'中? (2认同)

Rzv*_*.im 36

用同样的事情linq扩展方法:

var names = new string[] { "Ana", "Raz", "John" };
var numbers = new int[] { 1, 2, 3 };
var newList=names.SelectMany(
    x => numbers,
    (y, z) => { return y + z + " test "; });
foreach (var item in newList)
{
    Console.WriteLine(item);
}
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Mar*_*ade 24

根据史蒂夫的回答,最简单的表达方式是:

var combo = from Person in people
            from Car    in cars
            select new {Person, Car};
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amo*_*oss 9

A Tuple是笛卡尔积的良好类型:

public static IEnumerable<Tuple<T1, T2>> CrossJoin<T1, T2>(IEnumerable<T1> sequence1, IEnumerable<T2> sequence2)
{
    return sequence1.SelectMany(t1 => sequence2.Select(t2 => Tuple.Create(t1, t2)));
}
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Den*_*nis 7

扩展方法:

public static IEnumerable<Tuple<T1, T2>> CrossJoin<T1, T2>(this IEnumerable<T1> sequence1, IEnumerable<T2> sequence2)
{
    return sequence1.SelectMany(t1 => sequence2.Select(t2 => Tuple.Create(t1, t2)));
}
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并使用如下:

vals1.CrossJoin(vals2)
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