C++帮助.我在解决这个问题时遇到了问题

Question

这是我到目前为止的代码.我要做的是让程序显示超过60英寸的孩子数和他们的身高.该程序现在显示超过60英寸的儿童数量,但我还需要它来显示超过60英寸的儿童的身高.提前致谢!

#include <iostream>
using namespace std;
int main ()
{
    double childHeight[10];
    int numChildren = 0;

    for (int x = 0; x < 10; x = x + 1)
    {
        childHeight[x] = 0.0;
    }
    cout << "You will be asked to enter the height of 10 children." << endl;
    for (int x = 0; x < 10; x = x + 1)
    {
        cout << "Enter the height of child: ";
        cin >> childHeight[x];
    }
    cout << "The number of children over 60 inches are: "<< endl;
    for (int x = 0; x < 10; x = x + 1)
    {
        if (childHeight[x] > 60)
        {                
           numChildren = numChildren + 1;                
        }  
    }
    cout << numChildren << endl;
    system("pause"); 
    return 0;
}

Answer 1

这非常接近,如果是家庭作业,这是一个很好的第一次尝试,所以我不介意帮忙.

你已经有一个循环通过你的数组检查高度,所以这是一个简单的问题,添加到那,所以你:

• 检测到时输出高度超过60; 和
• 对打印的内容稍作修改,以便按顺序排列.

更改:

cout << "The number of children over 60 inches are: " << endl;
for (int x = 0; x < 10; x = x + 1)
{
    if (childHeight[x] > 60)
    {                
       numChildren = numChildren + 1;                
    }  
}
cout << numChildren << endl;

至:

cout << "The heights of children over 60 inches are: " << endl;    // ADD
for (int x = 0; x < 10; x = x + 1)
{
    if (childHeight[x] > 60)
    {                
       numChildren = numChildren + 1;                
       cout << "    " << childHeight[x] << endl;                  // ADD
    }  
}
cout << "The number of children over 60 inches are: " << endl;    // MOVE
cout << "    " << numChildren << endl;                            // CHNG

输出的改变numChildren只是添加空格,一个很好的格式化触摸.这应该导致输出类似于:

The heights of children over 60 inches are:
    62
    67
The number of children over 60 inches are:
    2

一些小的建议不会影响您的代码的性能可言,但我不认为我已经看到x = x + 1了几十年.C和C++这样做的方法通常是这样的++x.

此外,我倾向于选择\n到endl在大多数情况下.后者(见这里)输出一行结束并刷新缓冲区,这在某些情况下可能效率低下.