Oma*_*ali 3 python django django-rest-framework
我有一个用django_rest_framework. 我目前有一个对象是外键。当我发出一个 API 请求来获取一个对象时,它会显示外键 id 和仅 id。我希望它显示整个对象,而不仅仅是外键的 id。不知道该怎么做,因为它并没有在文档中真正展示如何做到这一点。
这是代码:
查看页面:
from users.models import Profile
from ..serializers import ProfileSerializer
from rest_framework import viewsets
class ProfileViewSet(viewsets.ModelViewSet):
queryset = Profile.objects.all()
lookup_field = 'user__username'
serializer_class = ProfileSerializer
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有一个引用用户的用户外键。
网址:
from users.api.views.profileViews import ProfileViewSet
from rest_framework.routers import DefaultRouter
router = DefaultRouter()
router.register(r'', ProfileViewSet, base_name='profile')
urlpatterns = router.urls
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序列化器:
class ProfileSerializer(serializers.ModelSerializer):
class Meta:
model = Profile
fields = (
'id',
'user',
'synapse',
'bio',
'profile_pic',
'facebook',
'twitter'
)
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这是它的样子:
HTTP 200 OK
Allow: GET, POST, HEAD, OPTIONS
Content-Type: application/json
Vary: Accept
[
{
"id": 1,
"user": 3,
"bio": "software engineer",
"profile_pic": "http://127.0.0.1:8000/api/user/profile/profile_pics/allsum-logo-1.png",
"facebook": "http://www.facebook.com/",
"twitter": "http://www.twitter.com/"
}
]
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JPG*_*JPG 12
depth=1在您Meta的序列化程序类中使用,
class ProfileSerializer(serializers.ModelSerializer):
class Meta:
model = Profile
fields = (
'id',
'user',
'synapse',
'bio',
'profile_pic',
'facebook',
'twitter'
)
depth = 1Run Code Online (Sandbox Code Playgroud)