AJ *_*ley 5 javascript arrays string javascript-objects
我有一系列的日期范围,例如:
["Mon-Tue", "Mon-Wed", "Mon-Thu", "Mon-Fri", "Mon-Sat", "Mon-Sun", "Tue-Mon", "Tue-Wed", "Tue-Thu", "Tue-Fri", "Tue-Sat", "Tue-Sun", ...]
我需要创建一个大对象,该对象将这些字符串中的每一个映射到包含所有相关日期的数组,如下所示:
var object = {
'Mon-Tue': ['Mon', 'Tue'],
'Mon-Wed': ['Mon', 'Tue', 'Wed'],
}
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为了提供帮助,我列出了一些可能的日子:
var days = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun']
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无需手动完成所有操作即可吗?
谢谢!
您可以使用 aMap来获取带有索引的天数并进行迭代,直到获得所有天数。
var days = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'],
daysMap = new Map(days.map((d, i) => [d, i])),
data = ["Mon-Tue", "Mon-Wed", "Mon-Thu", "Mon-Fri", "Mon-Sat", "Mon-Sun", "Tue-Mon", "Tue-Wed", "Tue-Thu", "Tue-Fri", "Tue-Sat", "Tue-Sun"],
result = Object.assign({}, ...data.map(d => {
var [start, end] = d.split('-'),
temp = [],
s = daysMap.get(start),
e = daysMap.get(end);
while (s !== e) {
temp.push(days[s]);
s++;
s %= days.length
}
temp.push(days[s]);
return { [d]: temp };
}));
console.log(result);Run Code Online (Sandbox Code Playgroud)
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Generator如果您愿意,您可以在想要的日子里度过。
function* getDays(from, to) {
var days = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'],
i = days.indexOf(from);
while (days[i % days.length] !== to) yield days[i++ % days.length];
yield days[i % days.length];
}
var data = ["Fri-Tue", "Mon-Tue", "Mon-Wed", "Mon-Thu", "Mon-Fri", "Mon-Sat", "Mon-Sun", "Tue-Mon", "Tue-Wed", "Tue-Thu", "Tue-Fri", "Tue-Sat", "Tue-Sun"],
result = Object.assign({}, ...data.map(d => ({ [d]: [...getDays(...d.split('-'))] })));
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另一种方法是使用明天对象,它给出明天的日期。
function* getDays(from, to) {
var tomorrow = { Sun: 'Mon', Mon: 'Tue', Tue: 'Wed', Wed: 'Thu', Thu: 'Fri', Fri: 'Sat', Sat: 'Sun' };
yield from;
while (from !== to) yield from = tomorrow[from];
}
var data = ["Fri-Tue", "Mon-Tue", "Mon-Wed", "Mon-Thu", "Mon-Fri", "Mon-Sat", "Mon-Sun", "Tue-Mon", "Tue-Wed", "Tue-Thu", "Tue-Fri", "Tue-Sat", "Tue-Sun"],
result = Object.assign({}, ...data.map(d => ({ [d]: [...getDays(...d.split('-'))] })));
console.log(result);Run Code Online (Sandbox Code Playgroud)
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