Pretty sure I'm over complicating my loops but unsure how to simplify

Question

As the title says I just need some help/advice on how I can simplify a part of my code. I get the output I want but it's obvious to see that the way I go about it is a bit excessive. What I'm trying to do in my program is pass the array

int [] myInches = {89,12,33,7,72,42,76,49,69,85,61,23};

Into my buildFeetArray method which just takes the array elements, divides them by 12 to get a new element value which is then put in a new array which is returned. Here is the method

 public static int[] buildFeetArray(int[] arrayParam) {
    int sum = 0;
    int lessthan1 = 0;
    int lessthan2 = 0;
    int lessthan3 = 0;
    int lessthan4 = 0;
    int lessthan5 = 0;
    int lessthan6 = 0;
    int lessthan7 = 0;
    int lessthan8 = 0;
    for (int count = 0; count < arrayParam.length; count++) {
        if (arrayParam[count] / 12 == 0) {
            lessthan1++;
        } else if (arrayParam[count] / 12 == 1) {
            lessthan2++;
        } else if (arrayParam[count] / 12 == 2) {
            lessthan3++;
        } else if (arrayParam[count] / 12 == 3) {
            lessthan4++;
        } else if (arrayParam[count] / 12 == 4) {
            lessthan5++;
        } else if (arrayParam[count] / 12 == 5) {
            lessthan6++;
        } else if (arrayParam[count] / 12 == 6) {
            lessthan7++;
        } else if (arrayParam[count] / 12 == 7) {
            lessthan8++;
        }
    }
    int[] newArray = {lessthan1, lessthan2, lessthan3, lessthan4, lessthan5, lessthan6, lessthan7, lessthan8};
    return newArray;
}

Ideally the output should be

int length = 8;
[0] = 1;
[1] = 2;
[2] = 1;
[3] = 1;
[4] = 1;
[5] = 2;
[6] = 2;
[7] = 2;

Which it is but there's definitely an easier way to go about it, if possible I'd like to avoid using lists and sticking with loops as I need practice with them. Thank you in advance for any advice/tips.

Answer 1

我为此编写了一些伪代码，其中您必须初始化一个数组，并在满足特定条件时递增数组的特定索引：

public static int [] buildFeetArray(int [] arrayParam) {
    int index;
    int [] lessthan = {0,0,0,0,0,0,0,0};
    for (int count = 0; count < arrayParam.length; count++) {
        index = arrayParam[count]/12;
        if(index < 8 ) {
            lessthan[index]++;
        }
    }
    return lessthan;
}

Answer 2

您可能要使用另一个数组来存储结果，例如：

public static  int[] buildFeetArray(int [] arrayParam) {

    int[] lessThanArray = new int[8];

    for (int count = 0; count < arrayParam.length; count++) {
        for (int remainder = 0; remainder < lessThanArray.length; remainder++) {

            if (arrayParam[count] / 12 == remainder) {

                lessThanArray[remainder]++;
                break; // exit from the inner "for" loop
            }
        }
    }

    return lessThanArray;
}

Answer 3

那这个呢：

int[] lessThanArray = new int[8];
for (int entry: myInches) {
    int lessThan = entry / 12;
    if (lessThan < 8) { 
        lessThanArray[lessThan]++;
    }
}

Answer 4

You could use a Switch block:

switch(arrayParam[count]/12){
  case 0:
    lessthan1++;
    break;
  case 1:
    lessthan2++;
    break;
  //and so on...
}

The effect is the same but it looks way more clean and it comes in handy in situations such like this one