Car*_*Jr. 1 variables jquery multidimensional-array jqplot
我想创建这种输出
var s1 = [['Sony',7],['Samsung',5],['LG',8]];
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这样我就可以用它来传递我的图形作为变量
从我的ajax的resutl出来
success: function(data){
//code to extract the data value here
var s1= need to create the data here
$.jqplot('chart',[s1],{ blah blah blah
}
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success函数中的"data"返回此表格布局
<table id="tblResult">
<tr class="tblRows">
<td class="clsPhone">Sony</td><td class="clsRating">7</td>
</tr>
<tr class="tblRows">
<td class="clsPhone">Samsung</td><td class="clsRating">5</td>
</tr>
<tr class="tblRows">
<td class="clsPhone">LG</td><td class="clsRating">8</td>
</tr>
</table>
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你能帮助我为此创造逻辑吗?
提前致谢
编辑: 我正在寻找类似以下的解决方案:
var s1;
$(".tblRows").each(function(){
// here I don't know exactly on what to do
//s1.push($(".clsPhone").text(),$(".clsRating").text()));
});
// all I wanted is to make the resul s1=[['Sony',7],['Samsung',5],['LG',8]];
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因为jqplot需要这种参数
s1=[['Sony',7],['Samsung',5],['LG',8]];
$.jqplot('chart',[s1],{
renderer:$.jqplot.PieRenderer,
rendererOptions:{
showDataLabels:true,
dataLabelThreshold:1
}
}
});
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所以我正在寻找一种方法来从数据中创建变量s1的值这可能吗?
Ada*_*son 14
var s1 = [];
$(".tblRows").each(function(){
// create a temp array for this row
var row = [];
// add the phone and rating as array elements
row.push($(this).find('.clsPhone').text());
row.push($(this).find('.clsRating').text());
// add the temp array to the main array
s1.push(row);
});
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