这些陈述是什么意思？

Question

#include<stdio.h>
void main() {
 int s[4][2]={
               {1,2},
               {3,4},
               {5,6},
               {7,8}
             };
int (*p)[2]; // what does this statement mean? (A)
int i,j,*pint;

for(i=0;i<=3;i++) {
 p=&s[i];
 pint=(int*)p;  // what does this statement mean? (B)
 printf("\n");
  for(j=0;j<=1;j++) {
    printf("%d",*(pint+j));
  }
}

我无法理解陈述'A'和'B'.如何做和做了什么？请非常清楚地解释一下.

Answer 1

声明A是声明

int (*p)[2];
      ^      p is
int (*p)[2];
     ^       p is a pointer
int (*p)[2];
        ^    p is a pointer to an array
int (*p)[2];
         ^   p is a pointer to an array of 2
int (*p)[2];
^^^          p is a pointer to an array of 2 int

语句B是带有嵌入式强制转换的赋值表达式

pint=(int*)p;
           ^  take the value in p (of type "pointer to array of 2 ints")
pint=(int*)p;
     ^^^^^^   take the value in p, convert it to 'pointer to int'
              even if it doesn't make sense to do so
pint=(int*)p;
^^^^^         take the value in p, convert it to 'pointer to int'
              and put the resulting value (whatever that may be) in pint

演员阵容很糟糕.尽可能避免演员表演.
^{(*)除非在非常特殊的情况下,例如<ctype.h>或变量函数或......}