在条件中加入MySQL中的两个表

-1 php mysql sql

第一:

id_look     id_first    name
1           1           Jhon
2           2           Mark
3           3           Mike
Run Code Online (Sandbox Code Playgroud)

第二

id     id_first     surnames
1      2            AAA
2      2            BBB
3      2            CCC
4      1            DDD
5      1            AAA
6      1            BBB
7      3            BBB
Run Code Online (Sandbox Code Playgroud)

如果姓氏是AND,我想得到所有id_look(相同id_first)AAABBB

所以结果应该是:

id_look
1
2  
Run Code Online (Sandbox Code Playgroud)

因为只有那个id_look包含AAAAND BBB的同时.

Mar*_*ith 5

SELECT id_look
FROM   `first` f
       JOIN `second` s
         ON s.id_first = f.id_first
WHERE  surnames IN ( 'AAA', 'BBB' )
GROUP  BY id_look
HAVING COUNT(DISTINCT surnames) = 2;  
Run Code Online (Sandbox Code Playgroud)