将多维对象数组简化为单个对象数组

Question

我有这个多维的对象数组-

const initialArray = [
  {
   name: 'aaa', 
   value:[{id:1, data:1}, {id:2, data:2}, {id:3, data:3}]
  },
  {
   name: 'bbb', 
   value:[{id:1, data:4}, {id:2, data:5}, {id:3, data:6}]
  },
  {
   name: 'ccc', 
   value:[{id:1, data:7}, {id:2, data:8}, {id:3, data:7}]
  },
  {
   name: 'ddd', 
   value:[{id:1, data:2}, {id:2, data:1}, {id:3, data:1}]
  }
]

我需要将其转换为该数组-

const finalArray = [
  {
    id: 1, aaa: 1, bbb: 4, ccc: 7, ddd: 2
  },
  {
    id: 2, aaa: 2, bbb: 5, ccc: 8, ddd: 1
  },
  {
    id: 3, aaa: 3, bbb: 6, ccc: 7, ddd: 1
  }
]

我现在有的解决方案是

initialArray.reduce((accum, arrayData) => {
  arrayData.value.forEach(element => {
    if (accum.some(el => el.id === element.id)) {
      accum.find(el => el.id === element.id)[arrayData.name] = element.data;
    } else {
        accum.push({ id: element.id, [arrayData.name]: element.data });
    }
  });
  return accum;
}, []);

有没有更好，更优雅的方法来做到这一点？我正在尝试通过减少迭代每个数组的次数以及更少的代码和更高的可读性来实现这一点。如您所见，每次迭代过程中的some和find都会增加迭代次数。有什么办法可以减少它？

Answer 1

function tranform(array) {
  const obj = {}
  
  array.forEach(({name, value}) => (value || []).forEach(({id, data}) => obj[id] = { id, ...obj[id], [name]: data } ))
  
  return Object.values(obj)
}

const initialArray = [
  {
   name: 'aaa', 
   value:[{id:1, data:1}, {id:2, data:2}, {id:3, data:3}]
  },
  {
   name: 'bbb', 
   value:[{id:1, data:4}, {id:2, data:5}, {id:3, data:6}]
  },
  {
   name: 'ccc', 
   value:[{id:1, data:7}, {id:2, data:8}, {id:3, data:7}]
  },
  {
   name: 'ddd', 
   value:[{id:1, data:2}, {id:2, data:1}, {id:3, data:1}]
  }
]

console.log(tranform(initialArray))