dplyr：带有 rbind_all 与 bind_rows 的数据框的向量列表

Question

我想将命名列表列表转换为数据框，其中一些缺少列。我可以使用已弃用的rbind_all但不能使用替代品成功做到这一点bind_rows

缺少列的示例列表（el3缺失b）

ex = list(el1=c(a=1, b=2, c=3), el2=c(a=2, b=3, c=4), el3=c(a=3, c=5))

rbind_all(ex)
# A tibble: 3 x 3
      a     b     c
  <dbl> <dbl> <dbl>
1     1     2     3
2     2     3     4
3     3    NA     5


> bind_rows(ex)
Error in bind_rows_(x, .id) : Argument 3 must be length 3, not 2

没有缺失的列

ex2 = list(el1=c(a=1, b=2, c=3), el2=c(a=2, b=3, c=4), el3=c(a=3, b=4, c=5))

rbind_all(ex2)
# A tibble: 3 x 3
      a     b     c
  <dbl> <dbl> <dbl>
1     1     2     3
2     2     3     4
3     3     4     5

bind_rows(ex2) # Output is transposed for some reason
# A tibble: 3 x 3
    el1   el2   el3
  <dbl> <dbl> <dbl>
1     1     2     3
2     2     3     4
3     3     4     5

如何rbind_all使用未弃用的函数复制行为？

Answer 1

请阅读以下示例?bind_rows：

# Note that for historical reasons, lists containg vectors are
# always treated as data frames. Thus their vectors are treated as
# columns rather than rows, and their inner names are ignored:
ll <- list(
  a = c(A = 1, B = 2),
  b = c(A = 3, B = 4)
)
bind_rows(ll)

# You can circumvent that behaviour with explicit splicing:
bind_rows(!!!ll)

因此，在您的情况下，您可以尝试：

ex = list(el1=c(a=1, b=2, c=3), el2=c(a=2, b=3, c=4), el3=c(a=3, c=5))
bind_rows(!!!ex)

# # A tibble: 3 x 3
#       a     b     c
#   <dbl> <dbl> <dbl>
# 1     1     2     3
# 2     2     3     4
# 3     3    NA     5

ex2 = list(el1=c(a=1, b=2, c=3), el2=c(a=2, b=3, c=4), el3=c(a=3, b=4, c=5))
bind_rows(!!!ex2)

# # A tibble: 3 x 3
#       a     b     c
#   <dbl> <dbl> <dbl>
# 1     1     2     3
# 2     2     3     4
# 3     3     4     5