我有以下用户定义的功能
vareas1 <- function(a, b, c) {
case_when(a == 1 ~ "top",
b == 1 ~ "left",
c == 1 ~ "right",
near(a, 1/3) && near(b, 1/3) && near(c, 1/3) ~ "centre"
)
}
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test2 <- vareas1(1/3, 1/3, 1/3)
正确评估
[1] "centre.
但是,当通过dplyr的mutate应用它时,它有时会产生NA.示例如下:
test1 <- data.frame("a" = c(1, 0, 0, 1/3),
"b" = c(0, 1, 0, 1/3),
"c" = c(0, 0, 1, 1/3)) %>% mutate(area1 = vareas1(a, b, c))
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这导致:
a b c area1
1 1.0000000 0.0000000 0.0000000 top
2 0.0000000 1.0000000 0.0000000 left
3 0.0000000 0.0000000 1.0000000 right
4 0.3333333 0.3333333 0.3333333 <NA>
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第[4]行中的NA而不是结果"中心"是出乎意料的,我不明白它来自哪里.
我认为这可能是由于列a,b和c的类,我调整了函数
vareas1_int <- function(a, b, c) {
case_when(a == as.integer(1 * 10e6) ~ "top",
b == as.integer(1 * 10e6) ~ "left",
c == as.integer(1 * 10e6) ~ "right",
near(a, as.integer(1/3 * 10e+6) &&
near(b, as.integer(1/3 * 10e+6)) &&
near(c, as.integer(1/3 * 10e+6))) ~ "centre"
)
}
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并将a,b,c更改为拟合整数:
test1 <- test1 %>%
mutate(a_mil = as.integer(a * 10e+6),
b_mil = as.integer(b * 10e+6),
c_mil = as.integer(c * 10e+6))
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但结果是一样的:
a b c area1 a_mil b_mil c_mil area_int
1 1.0000000 0.0000000 0.0000000 top 10000000 0 0 top
2 0.0000000 1.0000000 0.0000000 left 0 10000000 0 left
3 0.0000000 0.0000000 1.0000000 right 0 0 10000000 right
4 0.3333333 0.3333333 0.3333333 <NA> 3333333 3333333 3333333 <NA>
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谢谢您的帮助!
(这篇类似的帖子不包括我的问题.)
小智 6
您需要&而不是&&为了使您的函数与向量一起工作.
library(tidyverse)
vareas1 <- function(a, b, c) {
case_when(a == 1 ~ "top",
b == 1 ~ "left",
c == 1 ~ "right",
near(a, 1/3) & near(b, 1/3) & near(c, 1/3) ~ "centre"
)
}
data.frame("a" = c(1, 0, 0, 1/3),
"b" = c(0, 1, 0, 1/3),
"c" = c(0, 0, 1, 1/3)) %>% mutate(area1 = vareas1(a, b, c))
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