永川圭*_*川圭介 0 django django-forms
使用 Django 我想创建一个网站
而且我还想要以下条件：
简而言之，我想单击按钮并在服务器中运行 python 脚本。我已经按如下方式创建了按钮和调用函数脚本，但它会导致错误，因为返回值为 1 而不是渲染函数。
我怎样才能实现目标？
app_name/templates/app_name/index.html
<body>
<form action='some_function' method='GET'>
<button type='submit'>Click Here</button>
</form>
</body>
app_name/views.py
def some_function(request):
print("do something here")
return 1 # error is caused here but I don't want re-render
app_name/url.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.show_view, name='view'),
path('do_something', views.do_something, name='do_something')
]
谢谢！
You can use AJAX to run python functions asynchronously. If you want to run your python script when a button is clicked use the "onclick" event listener to call your AJAX function.
Use the URL you defined in your urls.py file and the view will get called asynchronously.
Your HTML
<body>
<input type='button' value='run function' onclick='runScript()'>
</body>
Javascript with JQuery will provide us with an easy way to make the AJAX call
function runScript() {
$.ajax({
url: 'do_something', //The URL you defined in urls.py
success: function(data) {
//If you wish you can do additional data manipulation here.
}
});
}
views.py
from django.http import HttpResponse
def some_function(request):
#Code to run
#More code to run
return HttpResponse('Return data to ajax call')
If I understood correctly you want to run python code when a button is clicked and the form's data is irrelevant.
If you are looking to actually use the form data then you may need to use e.preventDefault() in your ajax call to prevent the form from submitting and then send the data via your AJAX function.
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