Java 8将<Map <String,Object >>列出到List <Map <String,Object >>按键分组并按值计数

Question

我有以下地图列表

List<Map<String, Object>> listBeforeGroup = new ArrayList<Map<String, Object>>();

    Map<String, Object> m1 = new HashMap<String, Object>();
    m1.put("company", "LG");
    m1.put("billType", "A");
    m1.put("billPeriod", "09-2018");

    Map<String, Object> m2 = new HashMap<String, Object>();
    m2.put("company", "LG");
    m2.put("billType", "A");
    m2.put("billPeriod", "09-2018");

    Map<String, Object> m3 = new HashMap<String, Object>();
    m3.put("company", "LG");
    m3.put("billType", "A");
    m3.put("billPeriod", "09-2018");

    Map<String, Object> m4 = new HashMap<String, Object>();
    m4.put("company", "LG");
    m4.put("billType", "B");
    m4.put("billPeriod", "01-2019");

    Map<String, Object> m5 = new HashMap<String, Object>();
    m5.put("company", "LG");
    m5.put("billType", "B");
    m5.put("billPeriod", "01-2019");

    Map<String, Object> m6 = new HashMap<String, Object>();
    m6.put("company", "Samsung");
    m6.put("billType", "A");
    m6.put("billPeriod", "10-2018");

    Map<String, Object> m7 = new HashMap<String, Object>();
    m7.put("company", "Samsung");
    m7.put("billType", "A");
    m7.put("billPeriod", "10-2018");

    Map<String, Object> m8 = new HashMap<String, Object>();
    m8.put("company", "Samsung");
    m8.put("billType", "B");
    m8.put("billPeriod", "11-2018");

    listBeforeGroup.add(m1);listBeforeGroup.add(m2);
    listBeforeGroup.add(m3);listBeforeGroup.add(m4);
    listBeforeGroup.add(m5);listBeforeGroup.add(m6);

我如何获得此输出？

    //Desired Output - List<Map<String, Object>>
    //{company=LG, billType=A, billPeriod=09-2018, count=3}
    //{company=LG, billType=B, billPeriod=01-2019, count=2}
    //{company=Samsung, billType=A, billPeriod=10-2018, count=2}
    //{company=Samsung, billType=B, billPeriod=11-2018, count=1}

我试过这个,使用java 8流,但我无法获得所需的输出

List<Map<String, Object>> listAfterGroup = listBeforeGroup.stream().map(m -> m.entrySet().stream().collect(Collectors.toMap(p -> p.getKey(), p - >  p.getValue()))).collect(Collectors.toList());

并试过这个,顺便说一下这个解决方案给出了一张地图,但我不想要这个

Map<Object, Long> listAfterGroup = listBeforeGroup.stream().flatMap(m -> m.entrySet().stream()).collect(Collectors.groupingBy(Map.Entry::getKey,Collectors.counting()));

我想通过键"billPeriod"对地图进行分组,然后按值计算项目,然后生成新的地图列表.

Answer 1

可以创建一个类Company，后续的操作就变得简单多了。

class Company {
    String company;
    String billType;
    String billPeriod;

    public Company(String company, String billType, String billPeriod) {
        this.company = company;
        this.billType = billType;
        this.billPeriod = billPeriod;
    }

    // getters, setters, toString, etc
}

初始化列表：

List<Company> list = new ArrayList<>();
list.add(new Company("LG", "A", "09-2018"));
list.add(new Company("LG", "A", "09-2018"));
list.add(new Company("LG", "A", "09-2018"));
list.add(new Company("LG", "B", "01-2019"));
list.add(new Company("LG", "B", "01-2019"));
list.add(new Company("Samsung", "A", "10-2018"));
list.add(new Company("Samsung", "A", "10-2018"));
list.add(new Company("Samsung", "B", "11-2018"));

现在举个例子，您可以按公司名称分组：

Map<String, Long> map = list.stream().collect(
        Collectors.groupingBy(Company::getCompany, 
                              Collectors.mapping((Company c) -> c, Collectors.counting())));

现在，您可以更轻松地根据需要执行其他操作。另外，这里不是创建8 个映射，而是最终只处理1 个 list。