对元组列表中的日期时间对象进行排序

Question

我有一个元组列表，如下所示

[('John', datetime.datetime(2016, 11, 27, 18, 18), datetime.datetime(2017, 11, 27, 18, 18)), ('Adam', datetime.datetime(2017, 11, 27, 18, 18), datetime.datetime(2018, 11, 27, 18, 18), ('Adam', datetime.datetime(2001, 05, 27, 18, 18), datetime.datetime(2002, 09, 27, 18, 18)) ('Adam', datetime.datetime(2015, 11, 27, 18, 18), datetime.datetime(2016, 11, 27, 18, 18))]

我如何根据日期时间对象对此列表进行排序，基本上其格式Name,From date, To date

Answer 1

只需使用排序key的参数：from_date

import datetime

data = [('John', datetime.datetime(2016, 11, 27, 18, 18), datetime.datetime(2017, 11, 27, 18, 18)),
        ('Adam', datetime.datetime(2017, 11, 27, 18, 18), datetime.datetime(2018, 11, 27, 18, 18)),
        ('Adam', datetime.datetime(2001,  5, 27, 18, 18), datetime.datetime(2002,  9, 27, 18, 18)),
        ('Adam', datetime.datetime(2015, 11, 27, 18, 18), datetime.datetime(2016, 11, 27, 18, 18))]


result = sorted(data, key=lambda x: x[1])

for e in result:
    print(e)

输出

('Adam', datetime.datetime(2001, 5, 27, 18, 18), datetime.datetime(2002, 9, 27, 18, 18))
('Adam', datetime.datetime(2015, 11, 27, 18, 18), datetime.datetime(2016, 11, 27, 18, 18))
('John', datetime.datetime(2016, 11, 27, 18, 18), datetime.datetime(2017, 11, 27, 18, 18))
('Adam', datetime.datetime(2017, 11, 27, 18, 18), datetime.datetime(2018, 11, 27, 18, 18))