如何在C#中使用XmlSerializer将字节数组序列化为XML？

Question

假设我们有一个结构,它的数据由使用Marshal.PtrToStructure的非托管字节数组提供.

C#结构布局:

[StructLayout(LayoutKind.Sequential, Size = 128, CharSet = CharSet.Ansi, Pack = 1)]
public struct MNG_Y_Params
{
    public byte Number;
    public byte Version;
    [MarshalAs(UnmanagedType.ByValArray, SizeConst = 16)]
    public byte[] OliNumber;
    public byte InterfaceType;
}

字节数组表示未托管代码中的(ascii)字符串.

此结构是另一个结构的成员(具有一些其他成员):

public struct MyData
{
    public int ID;
    public StructType structType;
    [XmlElement(ElementName="MNG_Y_Params")]
    public MNG_Y_Params y_params;
    [XmlElement(ElementName = "SimpleStruct2")]
    public SimpleStruct2 ss2;
};

所以我们也有这个支持代码

public class XMLIgnore
{
    static public XmlSerializer customserialiser(MyData d)
    {
        XmlAttributes attrs = new XmlAttributes();
        attrs.XmlIgnore = true;
        XmlAttributeOverrides xmlOveride = new XmlAttributeOverrides();
        switch (d.structType)
        {
            case StructType.ST_1:
                xmlOveride.Add(typeof(MyData), "ss2", attrs);
                break;
            case StructType.ST_2:
                xmlOveride.Add(typeof(MyData), "y_params", attrs);
                break;
            default:
                break;
        }
        return new XmlSerializer(typeof(MyData), xmlOveride);
    }
}

和保存方法

    static void SaveToXml(object obj, string fileName, XmlSerializer writer)
    {
        //XmlSerializer writer = new XmlSerializer(obj.GetType());
        using (StreamWriter file = new StreamWriter(fileName))
        {
            writer.Serialize(file, obj);
        }
    }

对于示例,我们只生成一些数据.

        MNG_Y_Params yParams = new MNG_Y_Params();
        yParams.Version = 1;
        yParams.InterfaceType = 15;
        yParams.Number = 35;
        ASCIIEncoding enc = new ASCIIEncoding();
        yParams.OliNumber = enc.GetBytes("#1");

        MyData md1 = new MyData();
        md1.ID = 1;
        md1.structType = StructType.ST_1;
        md1.y_params = yParams;

        XmlSerializer writer = XMLIgnore.customserialiser(md1);
        SaveToXml(md1, @"C:\temp\dataOne.xml", writer);

预期的XML:

<?xml version="1.0" encoding="utf-8"?>
<MyData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>1</ID>
  <structType>ST_1</structType>
  <MNG_Y_Params>
    <Number>35</Number>
    <Version>1</Version>
    <OliNumber>#1</OliNumber>
    <InterfaceType>15</InterfaceType>
  </MNG_Y_Params>
</MyData>

结果XML:

<?xml version="1.0" encoding="utf-8"?>
<MyData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>1</ID>
  <structType>ST_1</structType>
  <MNG_Y_Params>
    <Number>35</Number>
    <Version>1</Version>
    <OliNumber>IzE=</OliNumber>
    <InterfaceType>15</InterfaceType>
  </MNG_Y_Params>
</MyData>

请关注字节数组成员(OliNumber)结果.

我们可以在这里使用一个属性吗？我错过了什么？

谢谢你的时间和帮助.

宜兰

供参考

Answer 1

在XmlSerializer默认情况下,将使用基64编码的编码的字节数组.如果您使用此网站并粘贴IzE=并解码,结果将是#1.您可以通过设置XmlElementAttribute.DataType来更改编码.我不确定是否[XmlElement(DataType = "string")]会奏效,但你可以尝试一下.使用[XmlElement(DataType = "hexBinary")]将生成原始字节.