not*_*bit 5 powershell winapi console-application windows-console
我正在尝试使用Windows API和SetConsoleMode调用更改output(CONOUT$)的Windows控制台模式.所以我修改了一个基于ConinMode.ps1(适用于输入)的PowerShell脚本来执行此操作.使用ConoutMode.exe和我的脚本,读取工作正常,并返回:
# .\ConoutMode.exe
mode: 0x3
ENABLE_PROCESSED_OUTPUT 0x0001 ON
ENABLE_WRAP_AT_EOL_OUTPUT 0x0002 ON
ENABLE_VIRTUAL_TERMINAL_PROCESSING 0x0004 off <====
DISABLE_NEWLINE_AUTO_RETURN 0x0008 off
ENABLE_LVB_GRID_WORLDWIDE 0x0010 off
# .\ConoutMode.ps1
OK! GetConsoleWindow handle : 0x1F06D6
Console Input Mode (CONIN) : 0x21f
Console Output Mode (CONOUT) : 0x3
但是,我的脚本和exe都无法编写模式.(可能是因为它认为我的输出句柄没有指向控制台？)
在PowerShell中:
# .\ConoutMode.exe set 0x000f
error: SetConsoleMode failed (is stdout a console?)
# .\ConoutMode.ps1 -Mode 7
OK! GetConsoleWindow handle : 0x1F06D6
old (out) mode: 0x3
SetConsoleMode (out) failed (is stdout a console?)
At C:\cygwin64\home\emix\win_esc_test\ConoutMode.ps1:112 char:9
+ throw "SetConsoleMode (out) failed (is stdout a console?)"
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : OperationStopped: (SetConsoleMode ...out a console?):String) [], RuntimeException
+ FullyQualifiedErrorId : SetConsoleMode (out) failed (is stdout a console?)
这是我ConoutMode.ps1的完整脚本:
param (
[int] $Mode
)
$signature = @'
[DllImport("kernel32.dll", SetLastError=true)]
public static extern IntPtr GetConsoleWindow();
[DllImport("kernel32.dll", SetLastError = true)]
public static extern IntPtr GetStdHandle(int nStdHandle);
[DllImport("kernel32.dll", SetLastError = true)]
public static extern uint GetConsoleMode(IntPtr hConsoleHandle, out uint lpMode);
[DllImport("kernel32.dll", SetLastError = true)]
public static extern uint SetConsoleMode(IntPtr hConsoleHandle, uint dwMode);
public const int STD_INPUT_HANDLE = -10;
public const int STD_OUTPUT_HANDLE = -11;
public const int ENABLE_PROCESSED_OUTPUT = 0x0001;
public const int ENABLE_WRAP_AT_EOL_OUTPUT = 0x0002;
public const int ENABLE_VIRTUAL_TERMINAL_PROCESSING = 0x0004;
public const int DISABLE_NEWLINE_AUTO_RETURN = 0x0008;
public const int ENABLE_LVB_GRID_WORLDWIDE = 0x0010;
'@
#----------------------------------------------------------
$WinAPI = Add-Type -MemberDefinition $signature -Name WinAPI -Namespace ConoutMode -PassThru
#$WinAPI = Add-Type -MemberDefinition $signature -Name WinAPI -Namespace IdentifyConsoleWindow -PassThru
$hwnd = $WinAPI::GetConsoleWindow()
if ($hwnd -eq 0) {
throw "Error: GetConsoleWindow returned NULL."
}
echo "OK! GetConsoleWindow handle : 0x$($hwnd.ToString("X"))"
function GetConIn {
$ret = $WinAPI::GetStdHandle($WinAPI::STD_INPUT_HANDLE)
if ($ret -eq -1) {
throw "Error: cannot get stdin handle"
}
return $ret
}
function GetConOut {
$ret = $WinAPI::GetStdHandle($WinAPI::STD_OUTPUT_HANDLE)
if ($ret -eq -1) {
throw "Error: cannot get stdout handle"
}
return $ret
}
function GetConInMode { #GetCOnsoleMode
$conin = GetConIn
$mode = 0
$ret = $WinAPI::GetConsoleMode($conin, [ref]$mode)
if ($ret -eq 0) {
throw "GetConsoleMode (in) failed (is stdin a console?)"
}
return $mode
}
function GetConOutMode {
$conout = GetConOut
$mode = 0
$ret = $WinAPI::GetConsoleMode($conout, [ref]$mode)
if ($ret -eq 0) {
throw "GetConsoleMode (out) failed (is stdout a console?)"
}
return $mode
}
function SetConInMode($mode) {
$conin = GetConIn
$ret = $WinAPI::SetConsoleMode($conin, $mode)
if ($ret -eq 0) {
throw "SetConsoleMode (in) failed (is stdin a console?)"
}
}
function SetConOutMode($mode) {
#$conout = GetConOut
# Different tack:
$conout = $hwnd
$ret = $WinAPI::SetConsoleMode($conout, $mode)
if ($ret -eq 0) {
throw "SetConsoleMode (out) failed (is stdout a console?)"
}
}
#----------------------------------------------------------
# MAIN
#----------------------------------------------------------
$oldInMode = GetConInMode
$oldOutMode = GetConOutMode
$newMode = $oldOutMode
$doit = $false
if ($PSBoundParameters.ContainsKey("Mode")) {
$newMode = $Mode
$doit = $true
}
if ($doit) {
echo "old (out) mode: 0x$($oldOutMode.ToString("x"))"
SetConOutMode $newMode
$newMode = GetConOutMode
echo "new (out) mode: 0x$($newMode.ToString("x"))"
} else {
echo "Console Input Mode (CONIN) : 0x$($oldInMode.ToString("x"))"
echo "Console Output Mode (CONOUT) : 0x$($oldOutMode.ToString("x"))"
}
所以在一天结束时,我想启用ENABLE_VIRTUAL_TERMINAL_PROCESSING控制台.
我正在使用的系统是:
---------------------------------------------------------
PowerShell Version : 6.1.1
OS Name : Microsoft Windows 8.1 (64-bit)
OS Version : 6.3.9600 [2018-11-16 00:50:01]
OS BuildLabEx : 9600.19179
OS HAL : 6.3.9600.18969
OS Kernel : 6.3.9600.18217
OS UBR : 19182
-------------------------------------------------------
with Privilege : Administrator
-------------------------------------------------------
ExecutionPolicy :
MachinePolicy : Undefined
UserPolicy : Undefined
Process : Undefined
CurrentUser : Undefined
LocalMachine : Bypass
Console Settings:
Type : ConsoleHost
OutputEncoding : Unicode (UTF-8)
Color Capability : 23
Registry VT Level : 1
CodePage (input) : 437
CodePage (output) : 437
我还启用了注册表项:HKCU:\Console\VirtualTerminalLevel,如其他地方所述.
问:如何使用PowerShell启用此位/标志？
我能想到的一些事情可能是错的:
我可能不会写入正确的输出缓冲区？(怎么找？)
请注意,设置一个屏幕缓冲区的输出模式不会影响其他屏幕缓冲区的输出模式.
执行脚本时,可能会创建一个新的输出缓冲区？(该怎么办？)
相关问题和链接:
该代码使用“GetStdHandle”来获取标准输入或标准输出。这些可能是控制台句柄 - 但这取决于进程的创建方式。如果您从控制台启动，并且 stdin/stdout 未重定向，那么您可能会获得控制台句柄。但这并不能保证。
无需请求 stdin/stdout，只需直接打开控制台句柄 - 您可以为CONIN$和”CreateFile” CONOUT$。CreateFile 的文档有一整节关于 Consoles 的内容。
更新：我做了一个要点来演示如何使用 CreateFile 从 PowerShell 中CONIN$打开CONOUT$。
| 归档时间： |
|
| 查看次数： |
392 次 |
| 最近记录： |