如何使用angular2-tree插件获取检查的树结构值

Dex*_*ter 4 javascript typescript angular

在这里,我使用我的 json 和 angular2 - 树组件生成动态树结构,直到现在一切正常,当我们选择特定名称必须被选为对象的事件时,我无法生成选择事件广告,如果是孩子在那里,我尝试了这个 URL,在文档中我也没有找到任何获取选定值的方法,所以请建议我。

https://angular2-tree.readme.io/docs

下面是我的代码

options = {
  useCheckbox: true
};
nodes;
data = {
  "info": {
    "laptop": {
    },
    "config": {
      "properties": {
        "ram": {
        },
        "processor": {
        },
        "hdd": {

        }
      }
    },
    "link": {

    },
    "name": {

    },
    "company": {
      "properties": {
        "model": {

        },
        "maker": {
          "type": "integer"
        },
        "country": {
          "type": "text"
        },
        "enterprise": {

        }

      }
    }
  }
};

check(){
  const results = Object.keys(this.data.info).map(k => ({
    name: k,
    children: this.data.info[k].properties
      ? Object.keys(this.data.info[k].properties).map(kk => ({ name: kk }))
      : []
  }));

  this.nodes = results;
}
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.html 代码

<button type="button" (click)="check()">click</button>

<hr>

<input id="filter" #filter (keyup)="tree.treeModel.filterNodes(filter.value)" placeholder="filter nodes" />
<button (click)="tree.treeModel.clearFilter()">Clear Filter</button>
<tree-root #tree [focused]="true" [options]="options" [nodes]="nodes"></tree-root>
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闪电战链接

https://stackblitz.com/edit/angular-kh28sg

Eli*_*seo 7

我不知道是否有更好的方法您可以使用 tree.treeModel.selectedLeafNodeIds 访问所选节点。您必须在检查 isSelected 或不之前查看文档/API

例如,如果您有一个按钮

 <!--I like pass as argument the property "treeModel" of #tree ("reference variable")-->
<button (click)="click(tree.treeModel)">sendData</button>
<tree-root #tree [focused]="true" [options]="options" [nodes]="nodes"></tree-root>
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你的功能点击可以像

click(tree:TreeModel)
{
  console.log(tree.activeNodes);
    Object.keys(tree.selectedLeafNodeIds).forEach(x=>{
      let node:TreeNode=tree.getNodeById(x);
      if (node.isSelected)
      {
         console.log("Selected:",node.data.name,
                     "Parent:",node.parent.data.name);
      }
  }) 
}
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注意:我分叉了你的 stackblitz

更新了用响应创建一个对象

click(tree: TreeModel) {
    console.log(tree.activeNodes);
    let result: any = {} //<--declare a variable
    Object.keys(tree.selectedLeafNodeIds).forEach(x => {
      let node: TreeNode = tree.getNodeById(x);
      if (node.isSelected) {
        console.log("Selected:", node.data.name,
          "Parent:", node.parent.data.name);
        if (node.parent.data.name) //if the node has parent
        {
          if (!result[node.parent.data.name]) //If the parent is not in the object
            result[node.parent.data.name] = {} //create

          result[node.parent.data.name][node.data.name] = true;
        }
        else {
          if (!result[node.data.name]) //If the node is not in the object
            result[node.data.name] = {} //create
        }
      }
    })
    console.log(result);
  }
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