Hor*_*zer 2 java mockito junit5
如果我使用以下方法进行 JUnit Mockito 测试,它会失败并显示org.opentest4j.AssertionFailedError: expected: not null。但是之前使用 verify() 和 Assertions.assertNotNull() 的 Mockito-(Parameter-)Test 是可以的。我做错了什么或我不明白什么?这是我的代码:
JUnit5/模拟测试:
@Mock
private MyentityAServiceImpl myentityAServiceImplmock;
@Captor
private ArgumentCaptor<MyentityA> myentityAArgument;
@Mock
private MyentityBdao myentityBdaomock;
@Mock
private MyentityB myentityBmock;
@Mock
private Logger loggermock;
@InjectMocks
private MyentityBServiceImpl teServiceImpl;
@Test
public void setMyentityAOfTeIfNullByLanr17() {
myentityBmock.setLanr7( "1234567" );
final MyentityA myentityA = new MyentityA();
mockito.when( myentityAServiceImplmock.findMyentityAByLanr17( myentityBmock.getLanr7() ) ).thenReturn( myentityA );
mockito.when( myentityBdaomock.save( myentityBmock ) ).thenReturn( myentityBmock );
myentityBmock = teServiceImpl.setMyentityAOfTeIfNullByLanr17( myentityBmock );
mockito.verify( myentityBmock ).setMyentityA( myentityAArgument.capture() );
Assertions.assertNotNull( myentityAArgument );
Assertions.assertNotNull( myentityBmock.getMyentityA() ); // --> org.opentest4j.AssertionFailedError: expected: not <null>
}
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测试方法:
public MyentityB setMyentityAOfTeIfNullByLanr17( final MyentityB entity ) {
MyentityA myentityA = entity.getMyentityA();
if ( myentityA != null ) {
return entity;
}
final String lanr17 = entity.getLanr7();
myentityA = myentityAServiceImpl.findMyentityAByLanr17( lanr17 );
if ( myentityA != null ) {
entity.setMyentityA( myentityA );
entity.setModuser( "root" );
return myentityBdao.save( entity );
}
return entity;
}
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抱歉,您的测试代码实在是太复杂了。
它过于精细地描述了在被测方法中操作的对象的调用流程。
除了你模拟很多东西:依赖关系,被测方法的参数。
最后,您将被测试方法的返回值分配给引用模拟参数的变量。这让事情变得很不清楚。
测试必须是直接可以理解的,而事实并非如此。
我花了大约 500 万才了解错误原因。对于这样一个简单的代码来说是很多的。
此断言失败:
Assertions.assertNotNull( myentityBmock.getMyentityA() ); // --> org.opentest4j.AssertionFailedError: expected: not <null>
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是因为在被测试的方法getMynEntityA() 中只能null像myentityBmock模拟一样设置一个字段,就像你在这里所做的那样对真实字段和相关的 getter 行为没有影响:
if ( myentityA != null ) {
entity.setMyentityA( myentityA ); // here you invoke a mocked method.
entity.setModuser( "root" );
return myentityBdao.save( entity );
}
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实际上,您的测试方式主要描述了被测试方法的调用流程,这就足够了:
mockito.verify( myentityBmock ).setMyentityA( myentityAArgument.capture() );
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因为您无法测试setMyentityA().
但我真的强烈建议您对您的方法进行单元测试,而不要嘲笑被测试方法的参数。
它可能看起来像:
@Test
public void setMyentityAOfTeIfNullByLanr17() {
MyentityB entityB = new MyentityB(...) ;
entityB.setLanr7( "1234567" );
final MyentityA myentityA = new MyentityA();
mockito.when( myentityAServiceImplmock.findMyentityAByLanr17( entityB.getLanr7() ) ).thenReturn( myentityA );
mockito.when( myentityBdaomock.save(entityB) ).thenReturn(entityB);
// action
MyentityB entityActualB = teServiceImpl.setMyentityAOfTeIfNullByLanr17(entityB);
// Perform content/logic assertion and no flow assertion :
Assertions.assertEquals(myEntityA, entityActualB.getMyEntityA());
Assertions.assertEquals("root", entityActualB.getModuser());
}
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根本没有经过测试的代码,但它应该可以帮助您理解我的意图。