使用LINQ将数组列表转换为KeyValuePairs列表

Question

我有一个数组列表:

var inp = new List<int[]>()
{
    new int[]{11,12,13},
    new int[]{21,22,23},
    new int[]{31,32,33},
    new int[]{41,42,43},
    new int[]{51,52,53},
};

我想把它转换成一对列表.我可以使用基本for循环以某种方式完成此操作.但我正在寻找使用LINQ的更简单的分拣机解决方案.

这是我到目前为止:

var outp = new List<KeyValuePair<int, int>>();

var rowlen = inp[0].Length;
for (int i = 0; i < inp.Count; i++)
    for (int j = 0; j < rowlen; j++)
        outp.Add(new KeyValuePair<int, int>(i * rowlen + j, inp[i][j]));

期望的输出如下所示:

0 11
1 12
2 13
3 21
4 22
5 23
6 31
7 32
8 33
9 41
10 42
11 43
12 51
13 52
14 53

任何帮助,将不胜感激.

Answer 1

尝试使用SelectMany来展平初始集合:

var result = inp
  .SelectMany(item => item)                             // Flatten
//  .Skip(1) // <- if you want to skip 1st item - 11
  .Select((item, index) => new KeyValuePair<int, int>(  // Selected as KeyValue
     index + 1, // + 1 if you want to start from 1
     item))
  .ToList();                                            // Materialized as List