Password Protecting an Excel file using Python

Question

I am trying to password protect an entire Excel file (same functionality as File > Protect Workbook > Encrypt with Password) using Python.

I have come across openpyxl and the protection features it offers (https://openpyxl.readthedocs.io/en/stable/protection.html) seems to fulfill this need. I have the following code:

from openpyxl import Workbook
from openpyxl import load_workbook

test_spreadsheet = "test.xlsx"
wb = load_workbook(test_spreadsheet)
wb.security.workbookPassword = "password"

However, I am getting the following error:

AttributeError: 'NoneType' object has no attribute 'workbookPassword'

Does anyone have an idea of what is causing this AttributeError? I have printed the sheetnames from wb and that is correctly printing the tabs in my Excel document.

Answer 1

对于默认构造的工作簿，该security属性默认初始化：

self.security = DocumentSecurity()

然而，通过阅读工作簿构建的工作簿不仅仅是默认构建的；而且是默认构建的。它们也由一个Parser对象操纵：

wb_part = _find_workbook_part(self.package) self.parser = WorkbookParser(self.archive, wb_part.PartName[1:], keep_links=self.keep_links) self.parser.parse() wb = self.parser.wb ... self.wb = wb

Parser.init默认构造 aWorkbook，但随后用源文档的属性覆盖特定属性：

self.wb.security = package.workbookProtection

这意味着对于没有安全设置的文件，导入的工作簿对象的属性值为None（security因此您的错误，因为None显然没有 attribute workbookPassword）。

然后，您的解决方案是创建一个 default WorkbookProtection()，将其分配给工作簿，然后设置工作簿密码。