NameError：名称“drive_service”未定义 Google API

Question

我想将照片上传到谷歌驱动器。我可以读取驱动器上的文件。但是当我为上传部分添加广告时，从第 49 行到第 55 行，我不断收到相同的错误。我不断收到错误“NameError: name 'drive_service' is not defined” 我已经导入了每个库，但仍然无法工作 这是我环顾四周的代码，但还没有看到解释它的帖子。

from __future__ import print_function
from googleapiclient.discovery import build
from httplib2 import Http
from oauth2client import file, client, tools
from apiclient.http import MediaFileUpload



# If modifying these scopes, delete the file token.json.
SCOPES = 'https://www.googleapis.com/auth/drive'

def main():
    """Shows basic usage of the Drive v3 API.
    Prints the names and ids of the first 10 files the user has access to."""
    # The file token.json stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    store = file.Storage('token.json')
    creds = store.get()
    if not creds or creds.invalid:
        flow = client.flow_from_clientsecrets('credentials.json', SCOPES)
        creds = tools.run_flow(flow, store)
    drive = build('drive', 'v3', http=creds.authorize(Http()))

    # Call the Drive v3 API
    results = drive.files().list(
        pageSize=10, fields="nextPageToken, files(id, name)").execute()
    items = results.get('files', [])

    if not items:
        print('No files found.')
    else:
        print('Files:')
        for item in items:
            print(u'{0} ({1})'.format(item['name'], item['id']))

if __name__ == '__main__':
    main()

file_metadata = {'name': 'photo.jpg'}
media = MediaFileUpload('photo.jpg',
                        mimetype='image/jpeg')
file = drive_service.files().create(body=file_metadata,
                                    media_body=media,
                                    fields='id').execute()
print ('File ID: %s' % file.get('id'))

Answer 1

您已经与此行建立了连接：

drive = build('drive', 'v3', http=creds.authorize(Http()))

呼叫时file = drive_service.files() 您必须传递刚刚建立的连接。因此drive_service，不要使用drive（您刚刚构建的）。

总结一下，您应该替换：

file = drive_service.files().create(body=file_metadata,
                                    media_body=media,
                                    fields='id').execute()

和：

file = drive.files().create(body=file_metadata,
                            media_body=media,
                            fields='id').execute()

你的脚本应该可以工作。

Answer 2

您可以直接使用service而不是 driver_service。它对我有用。

如代码示例所示

file_metadata = {'name': 'photo.jpg'}
media = MediaFileUpload('photo.jpg',
                        mimetype='image/jpeg')
file = service.files().create(body=file_metadata,
                                    media_body=media,
                                    fields='id').execute()

Answer 3

更改drive_service为drive或反之亦然