lau*_*kok 1 php string pdo integer prepared-statement
我认为这可能是我的pdo获取数据方法的一个缺陷,
public function fetch_all($query, $params = array())
{
try
{
# prepare the query
$stmt = $this->connection->prepare($query);
# if $params is not an array, let's make it array with one value of former $params
if (!is_array($params)) $params = array($params);
# execute the query
$stmt->execute($params);
# return the result
return $stmt->fetchAll(PDO::FETCH_ASSOC);
}
catch (PDOException $e)
{
# call the get_error function
$this->get_error($e);
}
}
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传递给此方法的所有参数都将成为字符串,但我需要整数用于sql LIMIT查询,如下所示
$sql = "
SELECT *
FROM root_pages
ORDER BY root_pages.pg_created DESC
LIMIT ?,?";
items = $connection->fetch_all($sql,array('0','6'));
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它返回此错误,
2SQLSTATE [42000]:语法错误或访问冲突:1064 SQL语法中有错误; 检查与MySQL服务器版本对应的手册,以便在第32行的"0","6"附近使用正确的语法
我该如何解决?
编辑:
正如所建议的,我将我的方法中的代码更改为以下内容,
# fetch a multiple rows of result as a nested array ( = multi-dimensional array)
public function fetch_all($query, $params = array())
{
try
{
# prepare the query
$stmt = $this->connection->prepare($query);
# if $params is not an array, let's make it array with one value of former $params
//if (!is_array($params)) $params = array($params);
foreach($params as $k=>$p){
if(is_numeric($p)){
$stmt->bindParam($k+1, $p, PDO::PARAM_INT);
}
else{
$stmt->bindParam($k+1, $p, PDO::PARAM_STR);
}
}
$stmt->execute();
# execute the query
//$stmt->execute($params);
# return the result
return $stmt->fetchAll(PDO::FETCH_ASSOC);
}
catch (PDOException $e)
{
# call the get_error function
$this->get_error($e);
}
}
$items = $connection->fetch_all($sql,array(0,6));
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然后我得到一个不同的错误,
2SQLSTATE [42000]:语法错误或访问冲突:1064 SQL语法中有错误; 检查与MySQL服务器版本对应的手册,以便在第32行的"6"附近使用正确的语法
编辑:
我把它改成了,
if(is_int($p)){..}
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但仍然得到同样的错误......叹息......
你应该用PDO :: PARAM_INT类型传递你的参数,如:
$sth->bindParam(':limit', $limit, PDO::PARAM_INT);
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