Nuñ*_*ada 2 java optional java-8
我有这段代码,我想在没有找到资源的情况下抛出异常
Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(com.tdk.web.exception.ResourceNotFoundException(“menu " +
addMenuAmount.getMenuId() + " not found "));
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但我得到了一个编译错误:
com.tdk.web.exception cannot be resolved to a type
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试试这个并确保它com.tdk.web.exception.ResourceNotFoundException是可访问的
Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(() -> new com.tdk.web.exception.ResourceNotFoundException("menu " +
addMenuAmount.getMenuId() + " not found "));
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注意 lambda() ->和引号"menu "。
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