也许只是另一个愚蠢的初学者问题:我在覆盖 django 模型表单时遇到问题,该表单当前在views.py 中使用以下代码。
下面的代码运行良好!
class PostCreateView(LoginRequiredMixin, CreateView):
model = Post
fields = ['title', 'content']
### want this instead of line 1 and 2 above --> form_class = PostCreateForm()
view_args = collections.namedtuple('view_args', ['page_title'])
view_args = view_args(page_title="Create Post")
def get_context_data(self, *args, **kwargs):
self.tgt_url_args = MyHelper.parse_tgt_url(self)
context = super(PostCreateView, self).get_context_data(*args, **kwargs)
context.update(MyHelper.get_context_metadata(self, self.tgt_url_args, PostCreateView.view_args))
return context
def form_valid(self, form):
form.instance.author = self.request.user
tgt_url_args = MyHelper.parse_tgt_url(self)
blog_article = Article.objects.get(pk=tgt_url_args.get('Article', '0'))
form.instance.article_field = blog_article
return super().form_valid(form)
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但是,我想覆盖表单以便向字段添加占位符。所以我将第 1 行和第 2 行替换为:
form_class = PostCreateForm()
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我还在 forms.py 中添加了以下内容:
from django import forms
from . models import Post
class PostCreateForm(forms.ModelForm):
class Meta:
model = Post
fields = ['title', 'content']
print('imported PostCreateForm')
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但是,当我导入并运行它时,出现以下错误:
'PostCreateForm' object is not callable
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我在这里做错了什么?
您不应传递构造的表单,而应仅传递对表单类的引用:
class PostCreateView(LoginRequiredMixin, CreateView):
model = Post
form_class = PostCreateForm # no parenthesis
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因此Django每次都会构造一个新的表单(取决于request.POST等的情况)。
如果需要向表单传递额外的参数,可以在get_form_kwargs[Django-doc]中指定字典。