如何从 Pandas 数据帧计算信息的香农熵?

ema*_*max 5 python entropy pandas

我有一个数据框df,其中包含从一个人Name_Give到另一个人的交易信息,Name_Receive如下所示:

df
    Name_Give    Name_Receive   Amount
0    John           Tom          300
1    Eva            Tom          700
2    Sarah          Tom          100
3    John           Tom          200
4    Tom            Eva          700
5    John           Eva          300
6    Carl           Eva          250
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对于每个Name_Receive j我想计算香农熵,S_j = -sum_i p_i \log p_i其中p_i是数量除以用户数量的总和j

S_Tom = - (300/1300 * np.log(300/1300) + 700/1300 * np.log(700/1300) + 100/1300 * np.log(100/1300) + 200/1300 * np.log(200/1300))

S_Eva = - (700/1250 * np.log(700/1250) + 300/1250 * np.log(300/1250) + 250/1250 * np.log(250/1250)

S_Tom = 1.157
S_Eva = 0.99
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我想要像df1下面这样的数据框

df1
     Name     Entropy
0    Tom      1.157
1    Eva      0.99
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San*_*apa 7

使用groupbytransfrom获取每组的总和,然后将Amount列值除以每组总和并计算值:

g_sum = df.groupby('Name_Receive')['Amount'].transform('sum')
values = df['Amount']/g_sum
df['Entropy'] = -(values*np.log(values))

df1 = df.groupby('Name_Receive',as_index=False,sort=False)['Entropy'].sum()

print(df1)
  Name_Receive   Entropy
0          Tom  1.156988
1          Eva  0.989094
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如果值包含 0,则在 groupby 之后的末尾使用:

df1['Entropy'] = df1['Entropy'].fillna(0)
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既然0*np.log(0)nan了它0使用fillna