从WinForms带来Powershell-Console

Question

我试图将我的powershell控制台放在前面,即使它被最小化.我找到了以下代码:

function Show-Process($Process, [Switch]$Maximize)
{
  $sig = '
    [DllImport("user32.dll")] public static extern bool ShowWindowAsync(IntPtr hWnd, int nCmdShow);
    [DllImport("user32.dll")] public static extern int SetForegroundWindow(IntPtr hwnd);
  '

  if ($Maximize) { $Mode = 3 } else { $Mode = 4 }
  $type = Add-Type -MemberDefinition $sig -Name WindowAPI -PassThru
  $hwnd = $process.MainWindowHandle
  $null = $type::ShowWindowAsync($hwnd, $Mode)
  $null = $type::SetForegroundWindow($hwnd) 
}
Show-Process -Process (Get-Process -Id $pid) 

它工作正常,但当我从Button Click事件调用该函数时,控制台不会显示.问题是什么？有没有办法在使用WinForms GUI时将powershell控制台置于前面？

以下是示例GUI代码:

function Show-Process($Process, [Switch]$Maximize)
{
  $sig = '
    [DllImport("user32.dll")] public static extern bool ShowWindowAsync(IntPtr hWnd, int nCmdShow);
    [DllImport("user32.dll")] public static extern int SetForegroundWindow(IntPtr hwnd);
  '

  if ($Maximize) { $Mode = 3 } else { $Mode = 4 }
  $type = Add-Type -MemberDefinition $sig -Name WindowAPI -PassThru
  $hwnd = $process.MainWindowHandle
  $null = $type::ShowWindowAsync($hwnd, $Mode)
  $null = $type::SetForegroundWindow($hwnd) 
}

Add-Type -AssemblyName System.Windows.Forms
[System.Windows.Forms.Application]::EnableVisualStyles()

$Form                            = New-Object system.Windows.Forms.Form
$Form.ClientSize                 = '446,266'
$Form.text                       = "Form"
$Form.TopMost                    = $false

$Button1                         = New-Object system.Windows.Forms.Button
$Button1.text                    = "button"
$Button1.width                   = 60
$Button1.height                  = 30
$Button1.location                = New-Object System.Drawing.Point(75,29)
$Button1.Font                    = 'Microsoft Sans Serif,10'

$Button1.Add_Click({
    Show-Process -Process (Get-Process -Id $pid) 
})

$Form.controls.AddRange(@($Button1))

[void]$Form.ShowDialog()

Answer 1

不幸的是，我无法完全修复它，但也许其他人可能会根据我的发现进一步帮助您：

首先，按钮单击事件中的进程与父 PowerShell 主机运行的进程空间不同。这可以很容易地证明，但会揭示函数中的$hwhdwith并在调用之前调用该函数：Write-Host $hwndShow-ProcessShow-ProcessShowDialog

Show-Process -Process (Get-Process -Id $pid) 
[void]$Form.ShowDialog()

换句话说：要修复此部分，您需要$Pid首先从 PowerShell 窗口捕获父级：

$Button1.Add_Click({
    Show-Process -Process $MyProcess 
})

$Form.controls.AddRange(@($Button1))

$MyProcess = Get-Process -Id $pid
Show-Process -Process $MyProcess
[void]$Form.ShowDialog()

上面的代码片段有效，但是一旦我删除（或注释掉）该行Show-Process -Process $MyProcess（在主机级别），它就会再次中断......