-2 php
session_start();
$username = $_SESSION['username'];
$db = new PDO("mysql:host=".DBHOST.";charset=utf8mb4;dbname=".DBNAME,
DBUSER, DBPASS);
function keygrabber($username) { //You need to pass a variable into this
function
global $db; //Gain access to the $db variable, which is out of scope due to
being inside of a function
$stmt = $db->prepare("SELECT * FROM keys WHERE username='$username'");
//Prepare the query
$stmt->execute(); //Execute the query
$results = $stmt->fetchAll(PDO::FETCH_ASSOC); //Fetch the query results
var_dump($results); //Dump the results
}
keygrabber($username);
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因此,如果我更改username='$username';为username='myactualusername';,它会起作用,即它不会显示任何错误或任何内容。
我基本上试图从与用户用户名匹配的键中获取所有数据。将来我会将其更改为 userID,但现在变量不起作用,因此我无法继续。
谢谢您的帮助
像这样尝试
$stmt = $db->prepare("SELECT * FROM keys WHERE username='$username'");
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希望它会有意义..