Spring-security - AccessDecisionVoter-impl不会被调用

fat*_*zzy 4 java voting spring-security


我正在尝试创建自定义AccessDecisionVoter,并在调用它时调试它.

我已经在每种方法中都提出了一个问题,但没有发生任何事情.

弹簧security.xml文件:

<bean id="accessDecisionManager" class="org.springframework.security.access.vote.UnanimousBased">
  <property name="decisionVoters">
     <list>
          <bean class="com.affiliates.server.security.voters.VoterTest">
              <property name="brandsApi"  ref="brandsApi"/>
          </bean>
        </list>
  </property>
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IBrandsApi.java

    public interface IBrandsApi {

    IHibernateBean getByPK(Integer id);

    @Secured({ "ROLE_BRAND_ADMIN" })    
    IHibernateBean update(IHibernateBean brand);

    @Secured({ "ROLE_BRAND_ADMIN" })    
    IHibernateBean insert(IHibernateBean brand);

    @Secured({ "ROLE_BRAND_ADMIN" })    
    ResultContainer getAll(IFilter filter);

    @Secured({ "ROLE_ADMIN" })  
    Integer delete(IFilter filter); 
}
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VoterTest.java(带有断点的空文件)

    public class VoterTest implements AccessDecisionVoter {
private IBrandsApi brandsApi;

    public IBrandsApi getBrandsApi() {
        return brandsApi;
    }

    public void setBrandsApi(IBrandsApi brandsApi) {
        this.brandsApi = brandsApi;
    }

        @Override
        public boolean supports(ConfigAttribute attribute) {
            System.out.println("here");
            return false;

        }

        @Override
        public boolean supports(Class<?> clazz) {
            System.out.println("here");
            return false;
        }

        @Override
        public int vote(Authentication authentication, Object object,
                Collection<ConfigAttribute> attributes) {
            System.out.println("here");
            return 0;
        }
    }
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顺便说一句,在应用程序加载/运行期间没有抛出异常谢谢

Ger*_*ger 6

您需要使用自定义AccessDecisionManager,否则使用默认值.你可以这样做

<global-method-security access-decision-manager-ref="accessDecisionManager"/>
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请查看文档以获取更多相关信息.

还有一件事:supports()你的选民的方法可能应该返回,true否则vote()不会被召唤.