如何在C中打印变量地址？

Question

当我运行此代码.

#include <stdio.h>

void moo(int a, int *b);

int main()
{
    int x;
    int *y;

    x = 1;
    y = &x;

    printf("Address of x = %d, value of x = %d\n", &x, x);
    printf("Address of y = &d, value of y = %d, value of *y = %d\n", &y, y, *y);
    moo(9, y);
}

void moo(int a, int *b)
{
    printf("Address of a = %d, value of a = %d\n", &a, a);
    printf("Address of b = %d, value of b = %d, value of *b = %d\n", &b, b, *b);
}

我一直在编译器中收到此错误.

/Volumes/MY USB/C Programming/Practice/addresses.c:16: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int *’
/Volumes/MY USB/C Programming/Practice/addresses.c:17: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int **’
/Volumes/MY USB/C Programming/Practice/addresses.c:17: warning: format ‘%d’ expects type ‘int’, but argument 3 has type ‘int *’
/Volumes/MY USB/C Programming/Practice/addresses.c: In function ‘moo’:
/Volumes/MY USB/C Programming/Practice/addresses.c:23: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int *’
/Volumes/MY USB/C Programming/Practice/addresses.c:24: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int **’
/Volumes/MY USB/C Programming/Practice/addresses.c:24: warning: format ‘%d’ expects type ‘int’, but argument 3 has type ‘int *’

你可以帮帮我吗？

谢谢

blargman

Answer 1

您想用来%p打印指针.从规格:

p 参数应该是指针void.指针的值以实现定义的方式转换为打印字符序列.

并且不要忘记演员表,例如

printf("%p\n",(void*)&a);

Answer 2

当您打算打印任何变量或指针的内存地址时,使用%d将不会执行该作业并将导致一些编译错误,因为您尝试打印出一个数字而不是一个地址,即使它确实有效,你有一个意图错误,因为内存地址不是数字.价值0xbfc0d878肯定不是数字,而是地址.

你应该使用的是什么%p.例如,

#include<stdio.h>

int main(void) {

    int a;
    a = 5;
    printf("The memory address of a is: %p\n", (void*) &a);
    return 0;
}

祝好运!