具有概率的枚举的随机值

Question

我有一个枚举,我想随机选择一个值,但不是真正随机的.我希望到目前为止,某些值不太可能被选中.这是我到目前为止所拥有的......

private enum Type{
        TYPE_A, TYPE_B, TYPE_C, TYPE_D, TYPE_E;

        private static final List<Type> VALUES =
            Collections.unmodifiableList(Arrays.asList(values()));
          private static final int SIZE = VALUES.size();
          private static final Random RANDOM = new Random();

          public static Type randomType()  {
            return VALUES.get(RANDOM.nextInt(SIZE));
          }
    }

是否有一种有效的方法为每个值分配概率？

代码从这里找到

Answer 1

几种方法,其中之一,类似于你的方法

private enum Type{
    TYPE_A(10 /*10 - weight of this type*/), TYPE_B(1), TYPE_C(5), TYPE_D(20), TYPE_E(7);

private int weight;

private Type(int weight) {
    this.weight = weight;
}

private int getWeight() {
    return weight;
}


    private static final List<Type> VALUES =
        Collections.unmodifiableList(Arrays.asList(values()));

    private int summWeigts() {
       int summ = 0;
       foreach(Type value: VALUES) 
          summ += value.getWeight();
       return summ;
    }
    private static final int SIZE = summWeigts();
    private static final Random RANDOM = new Random();

    public static Type randomType()  {
        int randomNum = RANDOM.nextInt(SIZE);
        int currentWeightSumm = 0;
        for(Type currentValue: VALUES) {
           if (randomNum > currentWeightSumm && 
               randomNum <= (currentWeightSumm + currentValue.getWeight()) {
             break;
           }
           currentWeightSumm += currentValue.getWeight();
        }

        return currentValue.get();
    }
}