我有一个像这样的对象:
{
"A": [ "-4927","8779","-9971","-23767" ],
"B": [ "-10617","-1456","3131","259" ],
"C": [ "-5185","1168","21501","18989" ],
"D": [ "2010","5664","2148","-674" ]
}
Run Code Online (Sandbox Code Playgroud)
我想转换成这个:
[
{
name: 'A',
data: ["-4927","8779","-9971","-23767"]
}, {
name: 'B',
data: ["-10617","-1456","3131","259"]
}, {
name: 'C',
data: ["-5185","1168","21501","18989"]
}, {
name: 'D',
data: ["2010","5664","2148","-674"]
}
]
Run Code Online (Sandbox Code Playgroud)
我使用了以下方法:
var newData = [];
$.each($.parseJSON(data), function(k, v) {
newData['name'] = k;
newData['data'] = v;
});
Run Code Online (Sandbox Code Playgroud)
但它只将最后一个密钥对值存储为newData.那是
name: 'D',
data: ["2010","5664","2148","-674"]
Run Code Online (Sandbox Code Playgroud)
据我所知,它会覆盖以前的数据并仅存储它获得的最后数据.但我无法解决这个问题.
任何帮助?
小智 8
您正在分配属性name而不是data直接newData将对象作为数组推入其中:
将你的循环改为:
var newData = [];
$.each($.parseJSON(data), function(k, v) {
const myNewData = {
name: k,
data: v
}
newData.push(myNewData);
});
Run Code Online (Sandbox Code Playgroud)
你可以使用 map
const oldData =
{ "A": [ "-4927","8779","-9971","-23767" ]
, "B": [ "-10617","-1456","3131","259" ]
, "C": [ "-5185","1168","21501","18989" ]
, "D": [ "2010","5664","2148","-674" ]
}
const newShape = ([ name, data ]) =>
({ name, data })
const newData =
Object.entries(oldData).map(newShape)
console.log(newData)
// [ { name: "A", data: [ "-4927","8779","-9971","-23767" ] }, ... ]Run Code Online (Sandbox Code Playgroud)
如果愿意,你可以编写lambda内联,但通常用可重用的部分编写程序会更好
const newData =
Object.entries(oldData).map(([ name, data ]) => ({ name, data }))
Run Code Online (Sandbox Code Playgroud)
jQuery可以使用$ .map映射对象- 注意不同的lambda
const newData =
$.map(oldData, (data, name) => ({ name, data }))
Run Code Online (Sandbox Code Playgroud)