我班上有很多后代:
PMyAncestor =^TMyAncestor;
TMyAncestor = object
public
constructor init;
destructor done; virtual;
// There are virtual methods as well
end;
PMyDescendant1 =^TMyDescendant1;
TMyDescendant1 = object ( TMyAncestor )
end;
PMyDescendant2 =^TMyDescendant2;
TMyDescendant2 = object ( TMyAncestor )
end;
PMyDescendant3 =^TMyDescendant3;
TMyDescendant3 = object ( TMyDescendant2 )
end;
procedure foo;
var
pMA1, pMA2, pMA3, pMA4 : PMyAncestor;
s : string;
begin
pMA1 := new( PMyAncestor, init );
pMA2 := new( PMyDescendant1, init );
pMA3 := new( PMyDescendant2, init );
pMA4 := new( PMyDescendant3, init );
try
s := some_magic( pMA1 ); // s := "TMyAncestor"
s := some_magic( pMA2 ); // s := "TMyDescendant1"
s := some_magic( pMA3 ); // s := "TMyDescendant2"
s := some_magic( pMA4 ); // s := "TMyDescendant3"
finally
dispose( pMA4, done );
dispose( pMA3, done );
dispose( pMA2, done );
dispose( pMA1, done );
end;
end;
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有没有办法获取其后代实例的类名?我不想因为这个原因创建一个虚方法(有成千上万的后代).我知道有typeOf(T)运营商.但它的返回类型是什么?好.指针.但是我能把它投射出去?演员PTypeInfo似乎是错的.
当我编译此代码并在编译的可执行文件中搜索类的名称时,找不到它们.
由此我得出结论,你要做的事情是不可能的.
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