如何在弹出窗口中显示输入错误?

Vik*_*dar 61 validation android popup android-edittext

我想EdiText在弹出窗口中显示所有字段的验证错误,如下图所示:

弹出窗口中的错误警报

据我所知,Android有drawables:

1)popup_inline_error.9.png

popup_inline_error.9.png

2)popup_inline_error_above.9.png

popup_inline_error_above.9

3)indicator_input_error.png

indicator_input_error.png

我可以EditText使用以下方法在右侧显示红色错误指示器:

Drawable err_indiactor = getResources().getDrawable(R.drawable.indicator_input_error);
mEdiText.setCompoundDrawablesWithIntrinsicBounds(null, null, err_indiactor, null);
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现在我也想显示错误信息,如图所示是第一张图片,但似乎我对此没有任何想法,虽然我认为它应该是自定义Toast.

Vik*_*dar 38

由于早期的答案是我的问题的解决方案,但我尝试了一种不同的方法来使用自定义Drawable图像而不是默认indicator_input_error图像.

默认Drawable

默认Drawable

自定义抽屉

自定义抽屉

所以,我刚刚EditText在我的布局xml文件中创建了两个,然后Listener用Java代码实现了一些EditText.

main.xml中

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical" android:layout_width="fill_parent"
    android:layout_height="fill_parent" android:padding="20dip"
    android:background="#222222">
    <EditText android:layout_width="match_parent"
        android:layout_height="wrap_content" android:hint="Username"
        android:id="@+id/etUsername" android:singleLine="true"
        android:imeActionLabel="Next"></EditText>
    <EditText android:layout_width="match_parent"
        android:inputType="textPassword"
        android:layout_height="wrap_content" android:hint="Password"
        android:id="@+id/etPassword" android:singleLine="true"
        android:imeActionLabel="Next"></EditText>
</LinearLayout>
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EditTextValidator.java

import java.util.regex.Pattern;

import android.app.Activity;
import android.graphics.Rect;
import android.graphics.drawable.Drawable;
import android.os.Bundle;
import android.text.Editable;
import android.text.TextWatcher;
import android.view.KeyEvent;
import android.view.inputmethod.EditorInfo;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.TextView.OnEditorActionListener;

public class EditTextValidator extends Activity {

    private EditText mUsername, mPassword;

    private Drawable error_indicator;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        // Setting custom drawable instead of red error indicator,
        error_indicator = getResources().getDrawable(R.drawable.emo_im_yelling);

        int left = 0;
        int top = 0;

        int right = error_indicator.getIntrinsicHeight();
        int bottom = error_indicator.getIntrinsicWidth();

        error_indicator.setBounds(new Rect(left, top, right, bottom));

        mUsername = (EditText) findViewById(R.id.etUsername);
        mPassword = (EditText) findViewById(R.id.etPassword);

        // Called when user type in EditText
        mUsername.addTextChangedListener(new InputValidator(mUsername));
        mPassword.addTextChangedListener(new InputValidator(mPassword));

        // Called when an action is performed on the EditText
        mUsername.setOnEditorActionListener(new EmptyTextListener(mUsername));
        mPassword.setOnEditorActionListener(new EmptyTextListener(mPassword));
    }

    private class InputValidator implements TextWatcher {
        private EditText et;

        private InputValidator(EditText editText) {
            this.et = editText;
        }

        @Override
        public void afterTextChanged(Editable s) {

        }

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {

        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before,
                int count) {
            if (s.length() != 0) {
                switch (et.getId()) {
                case R.id.etUsername: {
                    if (!Pattern.matches("^[a-z]{1,16}$", s)) {
                        et.setError("Oops! Username must have only a-z");
                    }
                }
                    break;

                case R.id.etPassword: {
                    if (!Pattern.matches("^[a-zA-Z]{1,16}$", s)) {
                        et.setError("Oops! Password must have only a-z and A-Z");
                    }
                }
                    break;
                }
            }
        }
    }

    private class EmptyTextListener implements OnEditorActionListener {
        private EditText et;

        public EmptyTextListener(EditText editText) {
            this.et = editText;
        }

        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {

            if (actionId == EditorInfo.IME_ACTION_NEXT) {
                // Called when user press Next button on the soft keyboard

                if (et.getText().toString().equals(""))
                    et.setError("Oops! empty.", error_indicator);
            }
            return false;
        }
    }
}
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现在我测试了它:

对于空的EditText验证:

假设用户点击该Username字段然后Softkeybord打开,如果用户按下Next键,则用户将聚焦到该Password字段并且Username字段保持为空,然后错误将显示如下图所示:

空文本 空文本

对于错误的输入验证:

1)我vikaS在用户名字段中键入文本,然后错误将如下图所示:

错误的用户名

2)我Password1在密码字段中键入文本,然后错误将如下图所示:

密码错误

注意:

这里我只使用自定义drawable,只有当用户将EditText字段留空并按下键盘上的Next键时,你可以在任何情况下使用它.只需要DrawablesetError()方法中提供对象.


SBK*_*SBK 34

试试这个..

final EditText editText=(EditText) findViewById(R.id.edit);

 editText.setImeActionLabel("",EditorInfo.IME_ACTION_NEXT);

        editText.setOnEditorActionListener(new OnEditorActionListener() {

            @Override
            public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
                if(actionId==EditorInfo.IME_ACTION_NEXT){
                    if( editText.getText().toString().trim().equalsIgnoreCase(""))
                        editText.setError("Please enter some thing!!!");
                    else
                        Toast.makeText(getApplicationContext(),"Notnull",Toast.LENGTH_SHORT).show();
                }
                return false;
            }
        });
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  • 而不是使用IME_ACTION_NEXT来触发验证我更喜欢setOnFocusChangeListener with if(!hasFocus)&& field.getText().toString().trim().equalsIgnoreCase(""))field.setError("请输入一些东西! !!"); 否则,当用户点击下一个TextEdit时,不会执行验证代码. (2认同)