如何从自定义异常过滤器返回JSON结果？

Question

我想创建一个自定义异常过滤器,它将捕获返回JSON结果的控制器操作中抛出的异常.

我想重构以下操作方法:

        public JsonResult ShowContent()
    {
        try
        {
            // Do some business logic work that might throw a business logic exception ...
            //throw new ApplicationException("this is a business exception");

            var viewModel = new DialogModel
                                {
                                    FirstName = "John",
                                    LastName = "Doe"
                                };

            // Other exceptions that might happen:
            //throw new SqlException(...);
            //throw new OtherException(...);
            //throw new ArgumentException("this is an unhandeled exception");

            return
                Json(
                    new
                        {
                            Status = DialogResultStatusEnum.Success.ToString(),
                            Page = this.RenderPartialViewToString("ShowContent", viewModel)
                        });
        }
        catch (ApplicationException exception)
        {
            return Json(new { Status = DialogResultStatusEnum.Error.ToString(), Page = exception.Message });
        }
        catch (Exception exception)
        {
            return Json(new { Status = DialogResultStatusEnum.Exception.ToString(), Page = "<h2>PROBLEM!</h2>" });
        }
    }
}

我想要做的是创建一个自定义异常过滤器属性,该属性将捕获操作中引发的任何异常,遵循以下逻辑:

1. 检查是否有异常
   • 不:回来
   • 是:
     • 如果是BusinessLogic异常 - 返回JSON结果
     • 如果是其他未处理的异常:
       • 日志
       • 使用不同的结果代码返回另一个JSON结果

Answer 1

我发现它可以使用中发现的代码解决这个问题,这篇文章(含有少量更改.)

public class HandleJsonExceptionAttribute : ActionFilterAttribute
{
    #region Instance Methods

    public override void OnActionExecuted(ActionExecutedContext filterContext)
    {
        if (filterContext.Exception != null)
        {
            filterContext.HttpContext.Response.StatusCode = (int)System.Net.HttpStatusCode.InternalServerError;
            filterContext.Result = new JsonResult()
            {
                JsonRequestBehavior = JsonRequestBehavior.AllowGet,
                Data = new
                {
                    Error = filterContext.Exception.Message
                }
            };
            filterContext.ExceptionHandled = true;
        }
    }

    #endregion
}