无法在 Spring Batch 中序列化此事务的访问

use*_*393 4 spring-mvc spring-batch spring-boot

我正在使用 Spring Batch 和 Spring Boot 来处理我的 Csv 文件。当我运行该应用程序时,我收到以下错误跟踪。

2018-08-27 16:23:35.694  INFO 12016 --- [nio-9004-exec-1] o.s.b.c.r.s.JobRepositoryFactoryBean     : No database type set, using meta data indicating: ORACLE
2018-08-27 16:23:36.025  INFO 12016 --- [nio-9004-exec-1] o.s.b.c.l.support.SimpleJobLauncher      : No TaskExecutor has been set, defaulting to synchronous executor.
2018-08-27 16:23:36.898  INFO 12016 --- [nio-9004-exec-1] o.s.b.f.xml.XmlBeanDefinitionReader      : Loading XML bean definitions from class path resource [org/springframework/jdbc/support/sql-error-codes.xml]
2018-08-27 16:23:36.965  INFO 12016 --- [nio-9004-exec-1] o.s.jdbc.support.SQLErrorCodesFactory    : SQLErrorCodes loaded: [DB2, Derby, H2, HSQL, Informix, MS-SQL, MySQL, Oracle, PostgreSQL, Sybase]
2018-08-27 16:23:37.005 ERROR 12016 --- [nio-9004-exec-1] o.a.c.c.C.[.[.[/].[dispatcherServlet]    : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.CannotSerializeTransactionException: PreparedStatementCallback; SQL [INSERT INTO BATCH_JOB_EXECUTION_CONTEXT (SHORT_CONTEXT, SERIALIZED_CONTEXT, JOB_EXECUTION_ID) VALUES(?, ?, ?)]; ORA-08177: can't serialize access for this transaction
; nested exception is java.sql.SQLException: ORA-08177: can't serialize access for this transaction
] with root cause

java.sql.SQLException: ORA-08177: can't serialize access for this transaction

        at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:450) ~[ojdbc7-12.1.0.1.jar!/:12.1.0.1.0]
        at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:399) ~[ojdbc7-12.1.0.1.jar!/:12.1.0.1.0]
        at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:1017) ~[ojdbc7-12.1.0.1.jar!/:12.1.0.1.0]
        at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:655) ~[ojdbc7-12.1.0.1.jar!/:12.1.0.1.0]
        at oracle.jdbc.driver.T4CTTI
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经过谷歌搜索后,我发现我们必须实例化JobRepositoryFactoryBean。所以我在 BatchConfiguration 中做了同样的事情,如下所示。

@Autowired
    private DataSource dataSource;
@Autowired
    private DataSourceTransactionManager transactionManager;   

 @Bean
        public JobRepositoryFactoryBean jobRepository() throws SQLException{
            JobRepositoryFactoryBean factoryBean = new JobRepositoryFactoryBean();
            factoryBean.setDatabaseType("ORACLE");
            factoryBean.setDataSource(dataSource);
            factoryBean.setTransactionManager(transactionManager);
            factoryBean.setIsolationLevelForCreate("ISOLATION_READ_UNCOMMITTED");
            return factoryBean;

        }
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Datasource ** 和 **TransactionManager bean 位于我的 DBConfiguration 中,如下所示。

@Bean
        public DataSource dataSource() throws SQLException
        {
            OracleDataSource dataSource = new OracleDataSource();
            dataSource.setUser("xxxxxx");
            dataSource.setPassword("xxxxx");
            dataSource.setURL("xxxxx");
            dataSource.setImplicitCachingEnabled(true);
            dataSource.setFastConnectionFailoverEnabled(true);



            return dataSource;

        }

@Bean(name="transactionManager")
        public PlatformTransactionManager  transactionManager() throws SQLException{

            DataSourceTransactionManager transactionManager = new DataSourceTransactionManager(this.dataSource());
            return transactionManager;

        }
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然后我收到以下错误

***************************
APPLICATION FAILED TO START
***************************

Description:

Field transactionManager in com.comcast.FileProcess.configuration.SprintgBatchConfiguration required a bean of type 'org.springframework.jdbc.datasource.DataSourceTransactionManager' that could not be found.
        - Bean method 'transactionManager' in 'DataSourceTransactionManagerAutoConfiguration.DataSourceTransactionManagerConfiguration' not loaded because @ConditionalOnMissingBean (types: org.springframework.transaction.PlatformTransactionManager; SearchStrategy: all) found bean 'transactionManager'


Action:

Consider revisiting the conditions above or defining a bean of type 'org.springframework.jdbc.datasource.DataSourceTransactionManager' in your configuration.
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任何人都可以帮助我解决这个问题并运行我的批处理过程。

Mah*_*ine 5

关于错误APPLICATION FAILED TO START,您需要使事务管理器 bean 定义方法返回实际类型,DataSourceTransactionManager而不是PlatformTransactionManager

@Bean(name="transactionManager")
    public DataSourceTransactionManager  transactionManager() throws SQLException{

        DataSourceTransactionManager transactionManager = new DataSourceTransactionManager(this.dataSource());
        return transactionManager;

    }
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关于该java.sql.SQLException: ORA-08177: can't serialize access for this transaction错误,看起来IsolationLevelForCreate仍然存在ISOLATION_SERIALIZABLE,并且您的数据库无法序列化事务。这可能是由于您的作业存储库未考虑在内。我会让该jobRepository方法返回作业存储库本身(如此处的示例所示而不是工厂 bean:

@Bean
    public JobRepository jobRepository() throws SQLException{
        JobRepositoryFactoryBean factoryBean = new JobRepositoryFactoryBean();
        factoryBean.setDatabaseType("ORACLE");
        factoryBean.setDataSource(dataSource);
        factoryBean.setTransactionManager(transactionManager);
        factoryBean.setIsolationLevelForCreate("ISOLATION_READ_UNCOMMITTED");
        return factoryBean.getObject();
    }
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这样,您的作业存储库将被正确配置,ISOLATION_READ_UNCOMMITTED并且您的数据库将不会尝试序列化事务。