如何从python中的列表中删除引用？

Question

我在我的代码中喜欢这个数组:

x = ['"google"','"facebook"',"youtube"]

我希望输出将是这样的

["google","facebook","youtube"]

怎么做？

Answer 1

使用str.strip和列表理解

In [1062]: x = ['"google"','"facebook"',"youtube"]

In [1063]: [i.strip('"') for i in x]
Out[1063]: ['google', 'facebook', 'youtube']

或者,您可以使用map而不是列表理解

In [1065]: list(map(lambda i: i.strip('"'), x))
Out[1065]: ['google', 'facebook', 'youtube']

你也可以使用 str.replace

In [1074]: [i.replace('"', '') for i in x]
Out[1074]: ['google', 'facebook', 'youtube']

比较所有三个,列表理解str.strip是最快的

In [1066]: %timeit([i.strip('"') for i in x])
The slowest run took 12.16 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 805 ns per loop

In [1067]: %timeit(list(map(lambda i: i.strip('"'), x)))
1000000 loops, best of 3: 1.52 µs per loop

In [1075]: %timeit([i.replace('"', '') for i in x])
The slowest run took 5.48 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 975 ns per loop